Building on top of what Finesse wrote, here is a simpler way to target the svg and change it's gradient.
This is what you need to do:
- Assign classes to each color stop defined in the gradient element.
- Target the css and change the stop-color for each of those stops using plain classes.
- Win!
Some benefits of using classes instead of :nth-child
is that it'll not be affected if you reorder your stops. Also, it makes the intent of each class clear - you'll be left wondering whether you needed a blue color on the first child or the second one.
I've tested it on all Chrome, Firefox and IE11:
.main-stop {
stop-color: red;
}
.alt-stop {
stop-color: green;
}
<svg class="green" width="100" height="50" version="1.1" xmlns="http://www.w3.org/2000/svg">
<linearGradient id="gradient">
<stop class="main-stop" offset="0%" />
<stop class="alt-stop" offset="100%" />
</linearGradient>
<rect width="100" height="50" fill="url(#gradient)" />
</svg>
See an editable example here:
https://jsbin.com/gabuvisuhe/edit?html,css,output