I was implementing the tower of hanoi problem to understand more about recursion. I was able to implement it using the 3 peg case, however, when I wanted to use more pegs (to generate less moves) I understand the Frame-Stewart solution where I have to break the number of disks I have and stack onto one peg and never touch that peg while I am transferring disks from the source peg to the destination pegs with all the intermediate pegs. However, I don't understand how write something like move(disks, 1, i, {2...K}) as a function. How can I write the names of all the pegs in the function prototype when I don't even know them from the beginning? I have given below what I worked up for the 3 disk solution, but I need help with the more general case.
// private member function: primitive/basic move of the top disk
// from the source peg to the destination peg -- and legality-check
void move_top_disk(int source, int dest)
{
cout << "Move disk " << towers[source].front() << " from Peg ";
cout << source+1 << " to Peg " << dest+1;
towers[dest].push_front(towers[source].front());
towers[source].pop_front();
if (true == is_everything_legal())
cout << " (Legal)" << endl;
else
cout << " (Illegal)" << endl;
}
// private member function: recursive solution to the 3 Peg Tower of Hanoi
void move(int number_of_disks, int source, int dest, int intermediate)
{
if (1 == number_of_disks)
{
moves++;
move_top_disk (source, dest);
}
else
{
moves++;
move (number_of_disks-1, source, intermediate, dest);
move_top_disk (source, dest);
move (number_of_disks-1, intermediate, dest, source);
}
}
I don't understand what kind of changes I would need to make to my "move" function to solve for a 6 pegs case. Thanks