Zend Framework 2 Part Route Assembly

Question

My Zend Framework 2 application has a route definition that's trying to mimic the default Zend Framework 1 route. It looks like:

        'router' => array(
            'routes' => array(
                'default' => array(
                    'type'    => 'segment',
                    'options' => array(
                        'route'    => '/[:controller[/:action]]',
                        'defaults' => array(
                            '__NAMESPACE__' => 'Application\Controller',
                            'controller'    => 'Index',
                            'action'        => 'index',
                        ),
                    ),
                    'may_terminate' => true,
                    'child_routes'  => array(
                        'wildcard' => array(
                            'type' => 'wildcard',
                        ),
                    ),
                ),
            ),
        ),

It matches routes just fine, but I can't assemble routes with arbitrary parameters using the Url view helper.

For example,

$this->url('default', array('controller' => 'test', 'action' => 'test', 'id' => 5));

results in /test/test instead of /test/test/id/5.

Does anyone know how to assemble partial routes like this? Or is there a better way of getting ZF1-style routes?

Blake Blake · Accepted Answer · 2012-08-13T14:11:42

It turns out that you need to specify the entire route name (including child routes) in the Url view helper.

Using the router defined in my question, the proper view helper call would look like:

$this->url('default/wildcard', array('controller' => 'test', 'action' => 'test', 'id' => 5));

which would result in a url of /test/test/id/5.

Zend Framework 2 Part Route Assembly

1 Answers