66
votes

My first symfony2 project is a list of guests (invited in an event) stored in a database. I have

  • created the entity class Guest with all variables for them (id, name, address, phone number etc.)
  • created the schema in the mysql db
  • created a route for "adding a guest" to a twig template
  • created a formType

and finally a "createGuest" method in the Controller and everything works fine.

I can't manage to remove a guest from the database. I have read every tutorial in the web, including the official Symfony2 book; all that it says is :

Deleting an Object

Deleting an object is very similar, but requires a call to the remove() method of the entity manager:

$em->remove($product);
$em->flush();

It does not say anything more than that (even the "Update an object" section is missing documentation) on how to connect the controller deleteAction($id) with the twig template. What I want to do is to list all guests with a viewGuests action and a viewGuests twig template, having a delete icon next to every row, which you should click to delete an entry. Simple, but I cannot find any documentation and do not know where to start from.

public function deleteGuestAction($id)
    {
        $em = $this->getDoctrine()->getEntityManager();
        $guest = $em->getRepository('GuestBundle:Guest')->find($id);

        if (!$guest) {
            throw $this->createNotFoundException('No guest found for id '.$id);
        }

        $em->remove($guest);
        $em->flush();

        return $this->redirect($this->generateUrl('GuestBundle:Page:viewGuests.html.twig'));
    }
3
Actually there is no error. I do not know how to interface the twig template. That means: you have a table that in each row a guest and some information (name, surname, phone number etc.) is displayed along with an <img> icon. I want to click on that button and get the row deleted from the database.Radolino
Is your Guest well loaded after the find() ? Else, try this prototype public function deleteGuestAction(Guest $guest) and delete your two first lines. Try also to var_dump your $guestJérôme Boé
Thanks for the replies. How should I send the Guest.name from the twig template to the controller ?Radolino
Why send the name ? You did well sending id.Jérôme Boé
This one gives me Controller "xxxxxBundle\Controller\PageController::deleteGuestAction()" requires that you provide a value for the "$id" argument (because there is no default value or because there is a non optional argument after this one).Radolino

3 Answers

92
votes

Symfony is smart and knows how to make the find() by itself :

public function deleteGuestAction(Guest $guest)
{
    if (!$guest) {
        throw $this->createNotFoundException('No guest found');
    }

    $em = $this->getDoctrine()->getEntityManager();
    $em->remove($guest);
    $em->flush();

    return $this->redirect($this->generateUrl('GuestBundle:Page:viewGuests.html.twig'));
}

To send the id in your controller, use {{ path('your_route', {'id': guest.id}) }}

6
votes

DELETE FROM ... WHERE id=...;

protected function templateRemove($id){
            $em = $this->getDoctrine()->getManager();
            $entity = $em->getRepository('XXXBundle:Templates')->findOneBy(array('id' => $id));

            if ($entity != null){
                $em->remove($entity);
                $em->flush();
            }
        }
3
votes

From what I understand, you struggle with what to put into your template.

I'll show an example:

<ul>
    {% for guest in guests %}
    <li>{{ guest.name }} <a href="{{ path('your_delete_route_name',{'id': guest.id}) }}">[[DELETE]]</a></li>
    {% endfor %}
</ul>

Now what happens is it iterates over every object within guests (you'll have to rename this if your object collection is named otherwise!), shows the name and places the correct link. The route name might be different.