How to check if object property exists with a variable holding the property name?

Question

I am checking for the existence of an object property with a variable holding the property name in question.

var myObj;
myObj.prop = "exists";
var myProp = "p"+"r"+"o"+"p";

if(myObj.myProp){
    alert("yes, i have that property");
};

This is undefined because it's looking for myObj.myProp but I want it to check for myObj.prop

Answer 1

var myProp = 'prop';
if(myObj.hasOwnProperty(myProp)){
    alert("yes, i have that property");
}

Or

var myProp = 'prop';
if(myProp in myObj){
    alert("yes, i have that property");
}

Or

if('prop' in myObj){
    alert("yes, i have that property");
}

Note that hasOwnProperty doesn't check for inherited properties, whereas in does. For example 'constructor' in myObj is true, but myObj.hasOwnProperty('constructor') is not.

Answer 2

You can use hasOwnProperty, but based on the reference you need quotes when using this method:

if (myObj.hasOwnProperty('myProp')) {
    // do something
}

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/hasOwnProperty

Another way is to use in operator, but you need quotes here as well:

if ('myProp' in myObj) {
    // do something
}

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/in

Answer 3

Thank you for everyone's assistance and pushing to get rid of the eval statement. Variables needed to be in brackets, not dot notation. This works and is clean, proper code.

Each of these are variables: appChoice, underI, underObstr.

if(typeof tData.tonicdata[appChoice][underI][underObstr] !== "undefined"){
    //enter code here
}

Answer 4

For own property :

var loan = { amount: 150 };
if(Object.prototype.hasOwnProperty.call(loan, "amount")) 
{ 
   //will execute
}

Note: using Object.prototype.hasOwnProperty is better than loan.hasOwnProperty(..), in case a custom hasOwnProperty is defined in the prototype chain (which is not the case here), like

var foo = {
      hasOwnProperty: function() {
        return false;
      },
      bar: 'Here be dragons'
    };

// https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/hasOwnProperty

To include inherited properties in the finding use the in operator: (but you must place an object at the right side of 'in', primitive values will throw error, e.g. 'length' in 'home' will throw error, but 'length' in new String('home') won't)

const yoshi = { skulk: true };
const hattori = { sneak: true };
const kuma = { creep: true };
if ("skulk" in yoshi) 
    console.log("Yoshi can skulk");

if (!("sneak" in yoshi)) 
    console.log("Yoshi cannot sneak");

if (!("creep" in yoshi)) 
    console.log("Yoshi cannot creep");

Object.setPrototypeOf(yoshi, hattori);

if ("sneak" in yoshi)
    console.log("Yoshi can now sneak");
if (!("creep" in hattori))
    console.log("Hattori cannot creep");

Object.setPrototypeOf(hattori, kuma);

if ("creep" in hattori)
    console.log("Hattori can now creep");
if ("creep" in yoshi)
    console.log("Yoshi can also creep");

// https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/in

Note: One may be tempted to use typeof and [ ] property accessor as the following code which doesn't work always ...

var loan = { amount: 150 };

loan.installment = undefined;

if("installment" in loan) // correct
{
    // will execute
}

if(typeof loan["installment"] !== "undefined") // incorrect
{
    // will not execute
}

Answer 5

A much more secure way to check if property exists on the object is to use empty object or object prototype to call hasOwnProperty()

var foo = {
  hasOwnProperty: function() {
    return false;
  },
  bar: 'Here be dragons'
};

foo.hasOwnProperty('bar'); // always returns false

// Use another Object's hasOwnProperty and call it with 'this' set to foo
({}).hasOwnProperty.call(foo, 'bar'); // true

// It's also possible to use the hasOwnProperty property from the Object
// prototype for this purpose
Object.prototype.hasOwnProperty.call(foo, 'bar'); // true

Reference from MDN Web Docs - Object.prototype.hasOwnProperty()

Answer 6

You can use hasOwnProperty() as well as in operator.

Answer 7

Several ways to check if an object property exists.

const dog = { name: "Spot" }

if (dog.name) console.log("Yay 1"); // Prints.
if (dog.sex) console.log("Yay 2"); // Doesn't print. 

if ("name" in dog) console.log("Yay 3"); // Prints.
if ("sex" in dog) console.log("Yay 4"); // Doesn't print.

if (dog.hasOwnProperty("name")) console.log("Yay 5"); // Prints.
if (dog.hasOwnProperty("sex")) console.log("Yay 6"); // Doesn't print, but prints undefined.

Answer 8

In the answers I didn't see the !! operator

if (!!myObj.myProp) //Do something

Answer 9

there are much simpler solutions and I don't see any answer to your actual question:

"it's looking for myObj.myProp but I want it to check for myObj.prop"

1. to obtain a property value from a variable, use bracket notation.
2. to test that property for truthy values, use optional chaining
3. to return a boolean, use double-not / bang-bang / (!!)

var myBadObj = undefined;
var myGoodObj = {prop:"exists"}
var myProp = "prop";

//1 use brackets. 
myGoodObj.myProp && console.log("wrong"); //dot is incorrect here
//(myBadObj[myProp]) //this would throw because undefined
myGoodObj[myProp] && console.log("1 - yes, i have that property");

// 2 use optional chaining.  tolerates undefined myBadObj
myBadObj?.[myProp] && console.log("2 - myBadObj has that");
myGoodObj?.[myProp] && console.log("2 - myGoodObj has that");

//3 get a boolean from the truthy value
console.log(!!myBadObj?.[myProp]);
console.log(!!myGoodObj?.[myProp]);