How do I convert a simple list of lists into a numpy array? The rows are individual sublists and each row contains the elements in the sublist.
7 Answers
If your list of lists contains lists with varying number of elements then the answer of Ignacio Vazquez-Abrams will not work. Instead there are at least 3 options:
1) Make an array of arrays:
x=[[1,2],[1,2,3],[1]]
y=numpy.array([numpy.array(xi) for xi in x])
type(y)
>>><type 'numpy.ndarray'>
type(y[0])
>>><type 'numpy.ndarray'>
2) Make an array of lists:
x=[[1,2],[1,2,3],[1]]
y=numpy.array(x)
type(y)
>>><type 'numpy.ndarray'>
type(y[0])
>>><type 'list'>
3) First make the lists equal in length:
x=[[1,2],[1,2,3],[1]]
length = max(map(len, x))
y=numpy.array([xi+[None]*(length-len(xi)) for xi in x])
y
>>>array([[1, 2, None],
>>> [1, 2, 3],
>>> [1, None, None]], dtype=object)
As this is the top search on Google for converting a list of lists into a Numpy array, I'll offer the following despite the question being 4 years old:
>>> x = [[1, 2], [1, 2, 3], [1]]
>>> y = numpy.hstack(x)
>>> print(y)
[1 2 1 2 3 1]
When I first thought of doing it this way, I was quite pleased with myself because it's soooo simple. However, after timing it with a larger list of lists, it is actually faster to do this:
>>> y = numpy.concatenate([numpy.array(i) for i in x])
>>> print(y)
[1 2 1 2 3 1]
Note that @Bastiaan's answer #1 doesn't make a single continuous list, hence I added the concatenate
.
Anyway...I prefer the hstack
approach for it's elegant use of Numpy.
I had a list of lists of equal length. Even then Ignacio Vazquez-Abrams
's answer didn't work out for me. I got a 1-D numpy array whose elements are lists. If you faced the same problem, you can use the below method
Use numpy.vstack
import numpy as np
np_array = np.empty((0,4), dtype='float')
for i in range(10)
row_data = ... # get row_data as list
np_array = np.vstack((np_array, np.array(row_data)))