For the first part, this procedure will apply a list of functions to a single argument, assuming that all the functions receive only one argument. A list with the results is returned
(define (apply-function-list flist element)
(map (lambda (f)
(f element))
flist))
For the second part, finding the maximum in the list is simple enough. For example, if the element is 2 and the list of functions is (list sin cos sqr sqrt):
(apply max
(apply-function-list (list sin cos sqr sqrt) 2))
EDIT :
Here's another possible solution, without using apply and in a single procedure:
(define (max-list-function flist element)
(foldr max -inf.0
(map (lambda (f) (f element))
flist)))
Use it like this:
(max-list-function (list sin cos sqr sqrt) 2)