Adding #pragma make_public(Type) not removing C3767 error

Question

I have an Assembly(A) which defines a Managed class which has a public constructor that takes two native types.

I have access to the Header files and compiled lib files which contain the native types.

I created a C++/CLI project and defined a ref class which contains a single public: static method that returns a public type defined in (A).

When I try to contstruct by passing in a native type I receive the `C3767 'YourType::TypeB': Candidate function(s) not accessible.

I've added #pragma make_public(Type) for the native types and any type they derive from but still not joy.

My class header:

#pragma once
#include "StdAfx.h"

using namespace System;
using namespace AssemblyA;

namespace NativeWrapper {
    ref class MyFactory
    {
    public:
        static AssemblyAType^ Build();
    };
}

My cpp file:

#include "StdAfx.h"

#pragma make_public(nativeObjectRoot)
#pragma make_public(nativeObjectDerived)


#include "MyFactory.h"

using namespace System;

using namespace NativeWrapper;

AssemblyAType^ MyFactory::Build()
{
  nativeObjectDerived* myNativeObject;
  //myNativeObject initialised and set up here
  return gcnew AssemblyAType(myNativeObject); <--C3767
}

I've looked and the managed type `AssemblyAType' has a public constructor with this signature. Can't seem to get the pragma to work??

So to summarize.

My C++/CLI project references a 3rd party Assembly that defines a type which takes a native type in its constructor. My project also has the header/lib files added/linked to.

Note: my code above isn't exactly what I've got but I've stripped out the pertinent parts.

See the comments section of this page: msdn.microsoft.com/en-us/library/19dh8yat(VS.80).aspx — Matt Smith

Matt Smith Matt Smith · Accepted Answer · 2012-02-09T14:49:43

make_public will make the the native type visibile to consumers of the assembly where you use it: http://msdn.microsoft.com/en-us/library/ms235607(v=vs.80).aspx. It will not change the visibility in an assembly you reference.

It seems the assembly you referenced should have had either a make_public for the native type, or simply declared the native type public (see Type visibilty for a header Share a header file shared between native and managed clients).

The below page seems to indicate that they should have gotten a warning for writing the method without making the native types public: http://msdn.microsoft.com/en-us/library/ms173713(v=vs.80).aspx

Perhaps you could post the third-party AssemblyAType code to make sure there's nothing else we're missing.

Adding #pragma make_public(Type) not removing C3767 error

1 Answers