How to pass a literal string value to the django url template tag

0
votes

I have a URL conf such as this:

url(r'^value-toggle/(?P<profile_id>\d{1,10})/(?P<on_or_off>on|off)/$', 
                           'clipfo.profile.views.value_toggle',
                           name='value-toggle'),

In my template, I am trying to link to it:

<a href="{% url value-toggle profile_id=profile.id on_or_off='off' %}">Turn off</a>.

I get the following error when viewing the page which contains the url tag:

Caught NoReverseMatch while rendering: Reverse for 'value-toggle' with arguments '()' and keyword arguments '{'profile_id': 5, 'on_or_off': '### FIX ME - bad template variable ###'}' not found.

Please note that "### FIX ME - bad template variable ###" is my TEMPLATE_STRING_IF_INVALID value.

How can i pass a literal "off" as the value of named param on_or_off to the url django template tag?

1
djangodjango-templates

1 Answers

2
votes

The future has saved me!

Just called 

{% load url from future %}

at the beginning of my template.

Using the url tag from future allowed me to do what I needed to do. I only had to wrap the name of the url in single quotes, such as:

<a href="{% url 'value-toggle' profile_id=profile.id on_or_off='off' %}">Turn off</a>.