How to parse this date format

Question

Hi folks I am trying to parse this format but not able to it .

Format : Fri Oct 21 2011 08:45:00 GMT 0530 (IST)

SimpleDateFormat("EEE MMM dd yyyy HH:mm:ss zzz ZZZZ")

Can some one explain me what is wrong in this ?

That 0530 has to be in RFC 822 format +0530 in order to get it parsed as such. You can't parse it without manipulating the string beforehand. — BalusC
I did change it to +0530 but still I am not able to parse it Fri Oct 21 2011 08:00:00 GMT+0530 (IST) new SimpleDateFormat("EEE MMM dd yyyy HH:mm:ss z (Z)") — user437066

Dave Newton Dave Newton · Accepted Answer · 2011-10-21T05:21:29

The format for your zzz is incorrect; the docs show that it needs to be in this format: GMT-05:30.

Also, since you have parentheses around the Z parameter, you need parentheses in your format string.

sdf = new SimpleDateFormat("EEE MMM dd yyyy HH:mm:ss z (Z)")
println sdf.parse("Fri Oct 21 2011 08:45:00 GMT+05:30 (IST)")
> Fri Oct 21 02:45:00 EDT 2011

How to parse this date format

1 Answers