140
votes

What I want to do is the following:

  1. taking JSON as input from text area in php
  2. use this input and convert it to JSON and pass it to php curl to send request.

this m getting at php from get of api this json string i want to pass to json but it is not converting to array

echo $str='{
        action : "create",
        record: {
            type: "n$product",
            fields: {
                n$name: "Bread",
                n$price: 2.11
            },
            namespaces: { "my.demo": "n" }
        }
    }';
    $json = json_decode($str, true);

the above code is not returning me array.

15
Do you need to convert json string to array OR do you want to forge an url from that data? What exactly is the question?Janis Veinbergs
then it is not giving Not giving what? You take a JSON formatted string from textarea and you convert it to JSON???PeeHaa
if you do the above json in my question json_decode(, true) does it retuns an arrayXMen
@Pekka Please check my quesiton again.XMen
invalid json problem this was .XMen

15 Answers

207
votes

If you pass the JSON in your post to json_decode, it will fail. Valid JSON strings have quoted keys:

json_decode('{foo:"bar"}');         // this fails
json_decode('{"foo":"bar"}', true); // returns array("foo" => "bar")
json_decode('{"foo":"bar"}');       // returns an object, not an array.
113
votes

Try this:

$data = json_decode($your_json_string, TRUE);

the second parameter will make decoded json string into an associative arrays.

34
votes

If you are getting the JSON string from the form using $_REQUEST, $_GET, or $_POST the you will need to use the function html_entity_decode(). I didn't realize this until I did a var_dump of what was in the request vs. what I copied into and echo statement and noticed the request string was much larger.

Correct Way:

$jsonText = $_REQUEST['myJSON'];
$decodedText = html_entity_decode($jsonText);
$myArray = json_decode($decodedText, true);

With Errors:

$jsonText = $_REQUEST['myJSON'];
$myArray = json_decode($jsonText, true);
echo json_last_error(); //Returns 4 - Syntax error;
11
votes

Use json_decode($json_string, TRUE) function to convert the JSON object to an array.

Example:

$json_string   = '{"a":1,"b":2,"c":3,"d":4,"e":5}';

$my_array_data = json_decode($json_string, TRUE);

NOTE: The second parameter will convert decoded JSON string into an associative array.

===========

Output:

var_dump($my_array_data);

array(5) {

    ["a"] => int(1)
    ["b"] => int(2)
    ["c"] => int(3)
    ["d"] => int(4)
    ["e"] => int(5)
}
6
votes

If you are getting json string from URL using file_get_contents, then follow the steps:

$url = "http://localhost/rest/users";  //The url from where you are getting the contents
$response = (file_get_contents($url)); //Converting in json string
 $n = strpos($response, "[");
$response = substr_replace($response,"",0,$n+1);
$response = substr_replace($response, "" , -1,1);
print_r(json_decode($response,true));
6
votes

your string should be in the following format:

$str = '{"action": "create","record": {"type": "n$product","fields": {"n$name": "Bread","n$price": 2.11},"namespaces": { "my.demo": "n" }}}';
$array = json_decode($str, true);

echo "<pre>";
print_r($array);

Output:

Array
 (
    [action] => create
    [record] => Array
        (
            [type] => n$product
            [fields] => Array
                (
                    [n$name] => Bread
                    [n$price] => 2.11
                )

            [namespaces] => Array
                (
                    [my.demo] => n
                )

        )

)
2
votes

You can convert json Object into Array & String.

$data='{"resultList":[{"id":"1839","displayName":"Analytics","subLine":""},{"id":"1015","displayName":"Automation","subLine":""},{"id":"1084","displayName":"Aviation","subLine":""},{"id":"554","displayName":"Apparel","subLine":""},{"id":"875","displayName":"Aerospace","subLine":""},{"id":"1990","displayName":"Account Reconciliation","subLine":""},{"id":"3657","displayName":"Android","subLine":""},{"id":"1262","displayName":"Apache","subLine":""},{"id":"1440","displayName":"Acting","subLine":""},{"id":"710","displayName":"Aircraft","subLine":""},{"id":"12187","displayName":"AAC","subLine":""}, {"id":"20365","displayName":"AAT","subLine":""}, {"id":"7849","displayName":"AAP","subLine":""}, {"id":"20511","displayName":"AACR2","subLine":""}, {"id":"28585","displayName":"AASHTO","subLine":""}, {"id":"45191","displayName":"AAMS","subLine":""}]}';

$b=json_decode($data);

$i=0;
while($b->{'resultList'}[$i])
{
    print_r($b->{'resultList'}[$i]->{'displayName'});
    echo "<br />";
    $i++;
}
1
votes

If you ever need to convert JSON file or structures to PHP-style arrays, with all the nesting levels, you can use this function. First, you must json_decode($yourJSONdata) and then pass it to this function. It will output to your browser window (or console) the correct PHP styled arrays.

https://github.com/mobsted/jsontophparray

1
votes
<?php
$str='{
    "action" : "create",
    "record" : {
                "type": "$product",
                "fields": {
                           "name": "Bread",
                           "price": "2.11"
                           },
                "namespaces": { "my.demo": "n" }
                }
    }';
echo $str;
echo "<br>";
$jsonstr = json_decode($str, true);
print_r($jsonstr);

?>

i think this should Work, its just that the Keys should also be in double quotes if they are not numerals.

1
votes

this my solution: json string $columns_validation = string(1736) "[{"colId":"N_ni","hide":true,"aggFunc":null,"width":136,"pivotIndex":null,"pinned":null,"rowGroupIndex":null},{"colId":"J_2_fait","hide":true,"aggFunc":null,"width":67,"pivotIndex":null,"pinned":null,"rowGroupIndex":null}]"

so i use json_decode twice like that :

$js_column_validation = json_decode($columns_validation);
$js_column_validation = json_decode($js_column_validation); 

var_dump($js_column_validation);

and the result is :

 array(15) { [0]=> object(stdClass)#23 (7) { ["colId"]=> string(4) "N_ni" ["hide"]=> bool(true) ["aggFunc"]=> NULL ["width"]=> int(136) ["pivotIndex"]=> NULL ["pinned"]=> NULL ["rowGroupIndex"]=> NULL } [1]=> object(stdClass)#2130 (7) { ["colId"]=> string(8) "J_2_fait" ["hide"]=> bool(true) ["aggFunc"]=> NULL ["width"]=> int(67) ["pivotIndex"]=> NULL ["pinned"]=> NULL ["rowGroupIndex"]=> NULL }
1
votes

Make sure that the string is in the following JSON format which is something like this:

{"result":"success","testid":"1"} (with " ") .

If not, then you can add "responsetype => json" in your request params.

Then use json_decode($response,true) to convert it into an array.

1
votes

There is a problem with the string you are calling a json. I have made some changes to it below. If you properly format the string to a correct json, the code below works.

$str = '{
        "action" : "create",
        "record": {
            "type": "n$product",
            "fields": {
                "nname": "Bread",
                "nprice": 2.11
            },
            "namespaces": { "my.demo": "n" }
        }
    }';

    $response = json_decode($str, TRUE);
    echo '<br> action' . $response["action"] . '<br><br>';
0
votes

Use this convertor , It doesn't fail at all: Services_Json

// create a new instance of Services_JSON
$json = new Services_JSON();

// convert a complexe value to JSON notation, and send it to the browser
$value = array('foo', 'bar', array(1, 2, 'baz'), array(3, array(4)));
$output = $json->encode($value);
print($output);
// prints: ["foo","bar",[1,2,"baz"],[3,[4]]]

// accept incoming POST data, assumed to be in JSON notation
$input = file_get_contents('php://input', 1000000);
$value = $json->decode($input);

// if you want to convert json to php arrays:
$json = new Services_JSON(SERVICES_JSON_LOOSE_TYPE);
0
votes

You can change a string to JSON as follows and you can also trim, strip on string if wanted,

$str     = '[{"id":1, "value":"Comfort Stretch"}]';
//here is JSON object
$filters = json_decode($str);

foreach($filters as $obj){
   $filter_id[] = $obj->id;
}

//here is your array from that JSON
$filter_id;
-3
votes
$data = json_encode($result, true);

echo $data;