Problem with sorting a list and displaying [duplicate]

Question

This question already has answers here:

Why does "return list.sort()" return None, not the list? (8 answers)

Closed 2 hours ago.

a = []
for i in range (100,200):
    if i % 12==0:
        a.append(i)
print(a[-1])

I get output as 192. But without index calling if I use sort function like

a = [] 
for i in range (100,200):
    if i % 12==0:
        a.append(i)
print(a.sort(reverse=True))

I get output as none. Just want to know why sort is not working ?

Answer 1

sort does not return the sorted list. Try like this:

a = []  
for i in range (100,200): 
    if i % 12==0: 
       a.append(i) 
a.sort(reverse=True)
print(a)

Answer 2

In case you want the sorted list to be returned, you could use

print(sorted(a, reverse=True))