Update
The solution offered by @TOndrej is far superior to what I wrote below, apart from one situation. If you need to take runtime decisions as to what class to create, then the approach below appears to be the optimal solution.
I've refreshed my memory of my own code base which also deals with this exact problem. My conclusion is that what you are attempting to achieve is impossible. I'd be delighted to be proved wrong if anyone wants to rise to the challenge.
My workaround is for the generic class to contain a field FClass which is of type class of TMyBaseClass. Then I can call my virtual constructor with FClass.Create(...). I test that FClass.InheritsFrom(T) in an assertion. It's all depressingly non-generic. As I said, if anyone can prove my belief wrong I will upvote, delete, and rejoice!
In your setting the workaround might look like this:
TMyBaseClass = class
public
constructor Create(test:integer); virtual;
end;
TMyBaseClassClass = class of TMyBaseClass;
TMyClass = class(TMyBaseClass)
public
constructor Create(test:integer); override;
end;
TClass1<T: TMyBaseClass> = class
private
FMemberClass: TMyBaseClassClass;
FItem: T;
public
constructor Create(MemberClass: TMyBaseClassClass); overload;
constructor Create; overload;
procedure Test;
end;
constructor TClass1<T>.Create(MemberClass: TMyBaseClassClass);
begin
inherited Create;
FMemberClass := MemberClass;
Assert(FMemberClass.InheritsFrom(T));
end;
constructor TClass1<T>.Create;
begin
Create(TMyBaseClassClass(T));
end;
procedure TClass1<T>.Test;
begin
FItem:= T(FMemberClass.Create(666));
end;
var
u: TClass1<TMyClass>;
begin
u:=TClass1<TMyClass>.Create(TMyClass);
u.Test;
end;
Another more elegant solution, if it is possible, is to use a parameterless constructor and pass in the extra information in a virtual method of T, perhaps called Initialize.