Hello I have this code:
Status ListFeatures(ServerContext* context, const Rectangle* rectangle,
ServerWriter<Feature>* writer) override {
auto lo = rectangle->lo();
auto hi = rectangle->hi();
long left = std::min(lo.longitude(), hi.longitude());
long right = std::max(lo.longitude(), hi.longitude());
long top = std::max(lo.latitude(), hi.latitude());
long bottom = std::min(lo.latitude(), hi.latitude());
for (const Feature& f : feature_list_) {
if (f.location().longitude() >= left &&
f.location().longitude() <= right &&
f.location().latitude() >= bottom &&
f.location().latitude() <= top) {
writer->Write(f);
}
}
return Status::OK;
}
This is server streaming RPC on Client Unary call.
I would like to not close the stream. Once the Client initiates the unary call I would like to keep the server stream "forever" so I can send messages whenever I like.
As far as I understand at the moment this line is executed:
return Status::OK;
The stream is getting closed. Is there any way I can keep it open so later I can send more server streaming messages?
