6
votes

Is there a way to indicate that two or more regex phrases can occur in any order? For instance, XML attributes can be written in any order. Say that I have the following XML:

<a href="home.php" class="link" title="Home">Home</a>
<a href="home.php" title="Home" class="link">Home</a>

How would I write a match that checks the class and title and works for both cases? I'm mainly looking for the syntax that allows me to check in any order, not just matching the class and title as I can do that. Is there any way besides just including both combinations and connecting them with a '|'?

Edit: My preference would be to do it in a single regex as I'm building it programatically and also unit testing it.

7
This is one of the many reasons regexes are not suited to parsing XML or HTML.Chas. Owens
regex ins't a programming language, you have to have things like @Josh Bush said above.. its not supposed to be a magic tool that can just parse things for you without any programming to control itRick
I like @Josh Bush's answer below a lot as it is what is working for me now that I came across thisRick
@Rick When you finally get a set of regexes and controlling code to the point where it can correctly handle HTML or XML you will have a parser. Why write a new parser when we already have so many good ones?Chas. Owens
No, you can't do it. That's one of the reasons you don't use regular expressions to parse HTML (or XML). Use a proper HTML parsing module. You cannot reliably parse HTML with regular expressions, and you will face sorrow and frustration down the road. As soon as the HTML changes from your expectations, your code will be broken. See htmlparsing.com/php for examples of how to properly parse HTML with PHP modules that have already been written, tested and debugged.Andy Lester

7 Answers

8
votes

No, I believe the best way to do it with a single RE is exactly as you describe. Unfortunately, it'll get very messy when your XML can have 5 different attributes, giving you a large number of different REs to check.

On the other hand, I wouldn't be doing this with an RE at all since they're not meant to be programming languages. What's wrong with the old fashioned approach of using an XML processing library?

If you're required to use an RE, this answer probably won't help much, but I believe in using the right tools for the job.

5
votes

Have you considered xpath? (where attribute order doesn't matter)

//a[@class and @title]

Will select both <a> nodes as valid matches. The only caveat being that the input must be xhtml (well formed xml).

4
votes

You can create a lookahead for each of the attributes and plug them into a regex for the whole tag. For example, the regex for the tag could be

<a\b[^<>]*>

If you're using this on XML you'll probably need something more elaborate. By itself, this base regex will match a tag with zero or more attributes. Then you add a lookhead for each of the attributes you want to match:

(?=[^<>]*\s+class="link")
(?=[^<>]*\s+title="Home")

The [^<>]* lets it scan ahead for the attribute, but won't let it look beyond the closing angle bracket. Matching the leading whitespace here in the lookahead serves two purposes: it's more flexible than matching it in the base regex, and it ensure that we're matching a whole attribute name. Combining them we get:

<a\b(?=[^<>]*\s+class="link")(?=[^<>]*\s+title="Home")[^<>]+>[^<>]+</a>

Of course, I've made some simplifying assumptions for the sake of clarity. I didn't allow for whitespace around the equals signs, for single-quotes or no quotes around the attribute values, or for angle brackets in the attribute values (which I hear is legal, but I've never seen it done). Plugging those leaks (if you need to) will make the regex uglier, but won't require changes to the basic structure.

2
votes

You could use named groups to pull the attributes out of the tag. Run the regex and then loop over the groups doing whatever tests that you need.

Something like this (untested, using .net regex syntax with the \w for word characters and \s for whitespace):

<a ((?<key>\w+)\s?=\s?['"](?<value>\w+)['"])+ />
1
votes

The easiest way would be to write a regex that picks up the <a .... > part, and then write two more regexes to pull out the class and the title. Although you could probably do it with a single regex, it would be very complicated, and probably a lot more error prone.

With a single regex you would need something like

<a[^>]*((class="([^"]*)")|(title="([^"]*)"))?((title="([^"]*)")|(class="([^"]*)"))?[^>]*>

Which is just a first hand guess without checking to see if it's even valid. Much easier to just divide and conquer the problem.

0
votes

An first ad hoc solution might be to do the following.

((class|title)="[^"]*?" *)+

This is far from perfect because it allows every attribute to occur more than once. I could imagine that this might be solveable with assertions. But if you just want to extract the attributes this might already be sufficent.

0
votes

If you want to match a permutation of a set of elements, you could use a combination of back references and zero-width negative forward matching.

Say you want to match any one of these six lines:

123-abc-456-def-789-ghi-0AB
123-abc-456-ghi-789-def-0AB
123-def-456-abc-789-ghi-0AB
123-def-456-ghi-789-abc-0AB
123-ghi-456-abc-789-def-0AB
123-ghi-456-def-789-abc-0AB

You can do this with the following regex:

/123-(abc|def|ghi)-456-(?!\1)(abc|def|ghi)-789-(?!\1|\2)(abc|def|ghi)-0AB/

The back references (\1, \2), let you refer to your previous matches, and the zero width forward matching ((?!...) ) lets you negate a positional match, saying don't match if the contained matches at this position. Combining the two makes sure that your match is a legit permutation of the given elements, with each possibility only occuring once.

So, for example, in ruby:

input = <<LINES
123-abc-456-abc-789-abc-0AB
123-abc-456-abc-789-def-0AB
123-abc-456-abc-789-ghi-0AB
123-abc-456-def-789-abc-0AB
123-abc-456-def-789-def-0AB
123-abc-456-def-789-ghi-0AB
123-abc-456-ghi-789-abc-0AB
123-abc-456-ghi-789-def-0AB
123-abc-456-ghi-789-ghi-0AB
123-def-456-abc-789-abc-0AB
123-def-456-abc-789-def-0AB
123-def-456-abc-789-ghi-0AB
123-def-456-def-789-abc-0AB
123-def-456-def-789-def-0AB
123-def-456-def-789-ghi-0AB
123-def-456-ghi-789-abc-0AB
123-def-456-ghi-789-def-0AB
123-def-456-ghi-789-ghi-0AB
123-ghi-456-abc-789-abc-0AB
123-ghi-456-abc-789-def-0AB
123-ghi-456-abc-789-ghi-0AB
123-ghi-456-def-789-abc-0AB
123-ghi-456-def-789-def-0AB
123-ghi-456-def-789-ghi-0AB
123-ghi-456-ghi-789-abc-0AB
123-ghi-456-ghi-789-def-0AB
123-ghi-456-ghi-789-ghi-0AB
LINES

# outputs only the permutations
puts input.grep(/123-(abc|def|ghi)-456-(?!\1)(abc|def|ghi)-789-(?!\1|\2)(abc|def|ghi)-0AB/)

For a permutation of five elements, it would be:

/1-(abc|def|ghi|jkl|mno)-
 2-(?!\1)(abc|def|ghi|jkl|mno)-
 3-(?!\1|\2)(abc|def|ghi|jkl|mno)-
 4-(?!\1|\2|\3)(abc|def|ghi|jkl|mno)-
 5-(?!\1|\2|\3|\4)(abc|def|ghi|jkl|mno)-6/x

For your example, the regex would be

/<a href="home.php" (class="link"|title="Home") (?!\1)(class="link"|title="Home")>Home<\/a>/