python - TypeError: 'float' object is not callable

Question

I am trying to use values from an array in the following equation:

for x in range(len(prof)):
    PB = 2.25 * (1 - math.pow(math.e, (-3.7(prof[x])/2.25))) * (math.e, (0/2.25)))

When I run I receive the following error:

Traceback (most recent call last):
  File "C:/Users/cwpapine/Desktop/1mPro_Chlavg", line 240, in <module>
    PB = float(2.25 * (1 - math.pow(math.e, (-3.7(prof[x])/2.25))) * (math.e, (0/2.25)))
TypeError: 'float' object is not callable

this is probably something simple but I can't quite figure it out. Any help would be greatly appreciated. Thanks in advance

you are missing an operation here : -3.7(prof[x]) it should be -3.7 * (prof[x]) or ... — mouad
I had the same exception in a class where I had a float attribute and a method with the same name. Renaming one of the two solved it for me — Giacomo Tecya Pigani

Unknown Unknown · Accepted Answer · 2011-08-03T16:23:30

There is an operator missing, likely a *:

-3.7 need_something_here (prof[x])

The "is not callable" occurs because the parenthesis -- and lack of operator which would have switched the parenthesis into precedence operators -- make Python try to call the result of -3.7 (a float) as a function, which is not allowed.

The parenthesis are also not needed in this case, the following may be sufficient/correct:

-3.7 * prof[x]

As Legolas points out, there are other things which may need to be addressed:

2.25 * (1 - math.pow(math.e, (-3.7(prof[x])/2.25))) * (math.e, (0/2.25)))
                                  ^-- op missing
                                                    extra parenthesis --^
               valid but questionable float*tuple --^
                                     expression yields 0.0 always --^

python - TypeError: 'float' object is not callable

3 Answers