7
votes

I'm new to JAXB and I want to change the default namespace prefix using EclipseLink MOXy. My package-info.java has the following code lines:

@javax.xml.bind.annotation.XmlSchema (
namespace="http://namespace.mysite.com/",
xmlns = { 
    @javax.xml.bind.annotation.XmlNs(prefix="myns", 
               namespaceURI="http://namespace.mysite.com/")
},
elementFormDefault = javax.xml.bind.annotation.XmlNsForm.UNQUALIFIED
)
package com.core.mymodel;

And my jaxb.properties file has the following line:

javax.xml.bind.context.factory=org.eclipse.persistence.jaxb.JAXBContextFactory

I have added eclipselink.jar to the CLASSPATH, both package-info.java and jaxb.properties files are in the same package as my model classes, however, when I run the program I get the following error message:

javax.xml.bind.JAXBException: Provider org.eclipse.persistence.jaxb.JAXBContextFactory        not found
- with linked exception:
[java.lang.ClassNotFoundException: org.eclipse.persistence.jaxb.JAXBContextFactory]
at javax.xml.bind.ContextFinder.newInstance(Unknown Source)
at javax.xml.bind.ContextFinder.find(Unknown Source)
at javax.xml.bind.JAXBContext.newInstance(Unknown Source)
at javax.xml.bind.JAXBContext.newInstance(Unknown Source)
at javax.xml.bind.JAXBContext.newInstance(Unknown Source)

I have tried this with EclipseLink versions 2.3.0 and 2.0.2 and still got the same error message. Does anyone happen to know what could be the problem?

Many thanks in advance

2
What environment are you running your application in Java SE, application server, OSGi? - bdoughan
Hi Blaise, I'm using Java SE v1.6 - Khutsi
Are you creating the JAXBContext on an array of classes or a String context path? - bdoughan
I'm creating the JAXBContext on a String context path. Here is the code line: JAXBContext context = JAXBContext.newInstance("com.core.mymodel"); - Khutsi
Just for clarification, "com.core.mymodel" is the name of the package that contains the model classes and the jaxb.index file. - Khutsi

2 Answers

4
votes

You appear to have your jaxb.properties file correct based on the exception message:

javax.xml.bind.JAXBException: Provider org.eclipse.persistence.jaxb.JAXBContextFactory        not found
- with linked exception:
[java.lang.ClassNotFoundException: org.eclipse.persistence.jaxb.JAXBContextFactory]
at javax.xml.bind.ContextFinder.newInstance(Unknown Source)
at javax.xml.bind.ContextFinder.find(Unknown Source)
at javax.xml.bind.JAXBContext.newInstance(Unknown Source)
at javax.xml.bind.JAXBContext.newInstance(Unknown Source)
at javax.xml.bind.JAXBContext.newInstance(Unknown Source)

To confirm that org.eclipse.persistence.jaxb.JAXBContextFactory is on your classpath can you try:

JAXBContext jc = JAXBContextFactory.createContext("com.core.mymodel", null);

To do a more basic confirmation can you run:

System.out.println(org.eclipse.persistence.Version.getVersion());

For More Information

0
votes

Use it as a System property

System.setProperty("javax.xml.bind.JAXBContextFactory", "org.eclipse.persistence.jaxb.JAXBContextFactory");