0
votes

I have a user entity, with a field isSubscribed.

I want to show the status of this (boolean) as a checked or unchecked checkbox in a form.

Normally I would get this value in my formtype from a query but that seems overkill.

I want to do something like this:

$builder
        ->add('isSubscribed', CheckboxType::class, [
            'label'    => 'Subscribe to weekly update',
            'attr' => array('checked' => function(User $user){
                return $user->getIsSubscribed();
            }),
            'required' => false,
        ])
    ;

But I get an error:

Closure could not be converted to string

Here's my formtype:

<?php

namespace App\Form;

use App\Entity\User;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\Extension\Core\Type\CheckboxType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolver;

class AccountFormType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options): void
    {
        $builder
            ->add('isSubscribed', CheckboxType::class, [
                'label'    => 'Subscribe to weekly update',
                'required' => false,
            ])
        ;
    }

    public function configureOptions(OptionsResolver $resolver)
    {
        $resolver->setDefaults([
            'data_class' => User::class,
        ]);
    }
}

In my User entity:

/**
     * @ORM\Column(type="boolean")
     */
    private $isSubscribed;
1

1 Answers

2
votes

If your form has a data_class linked to your User, the value will be set automatically.

Otherwise, you can do something like this

->add('isSubscribed', CheckboxType::class, [
    'label'    => 'Subscribe to weekly update',
    'data' => $user->getIsSubscribed(),
    'required' => false,
])

where $user can be passed through form options if you don't have it