I'm currently attempting to create a stream using a macro, as shown below:
(define-syntax create-stream
(syntax-rules (using starting at with increment )
[(create-stream name using f starting at i0 with increment delta)
(letrec
([name (lambda (f current delta)
(cons current (lambda () (name (f (+ current delta) delta)))))])
(lambda () (name f i0 delta)))
]))
What happens though is I get a compilation error later on when I try to pass it the following lambda function, which says "lambda: not an identifier, identifier with default, or keyword".
(create-stream squares using (lambda (x) (* x x)) starting at 5 with increment 2)
What I suspect is happening is that by attempting to use lambda in a macro, it's shadowing the actual lambda function in Racket. If this is true, I'm wondering in what way one can create a stream without using lambda, since as far as I can tell, there needs to be a function somewhere to create said stream.
Also this is a homework problem, so I do have to use a macro. My equivalent function for creating the stream would be:
(define create-stream
(letrec ([name (lambda (f current delta) (cons current (lambda () (name (f (+ current delta) delta)))))])
(lambda () (name f i0 delta))))
define namepart, try keeping(define name (lambda () (fn i0))as is, addingnameafter it, and see what happens. but you really should post a new question with all this. - Will Ness