Rxjs pipes - multiple operators in one pipe or multiple pipes?

Question

I like the readability provided by

observable
  .pipe(operator1)
  .pipe(operator2)
  .pipe(operator3)
  .subscribe()

And it reminds me of a chain of thens for a promise.

But I know this is in every documentation example

observable
  .pipe(
    operator1,
    operator2,
    operator3
).subscribe()

Is there something lost in doing the first thing over the second? I am probably missing some crucial information here and maybe it's very obvious, actually. Thanks for the help.

What do you mean lost? The first example runs more code because you execute pipe multiple times. The outcome is the same. — frido

Hamid Taebi Hamid Taebi · Accepted Answer · 2020-11-19T21:12:43

certainly they are equal and they have same result.

both of them is equal to

operator3(operator2(operator1(observable))).subscribe()

Rxjs pipes - multiple operators in one pipe or multiple pipes?

1 Answers