What is the -i option while compiling hs file using GHC and how to do same in GHCi?

0
votes

Ok, I've been using the -i compile option to specify the folder to some haskell source when I compile using GHC.

ghc -threaded -i/d/haskell/src --make xxx.hs

I understand it uses those files as 'libraries' while compiling but can i do same in GHCi?

I usually import haskell prepackaged lib e.g. import Data.List or :m +Data.List.

I tried import /d/haskell/src -- does not work!

EDIT From Haskell doc: Chapter 2 Using GHCi Note that in GHCi, and ––make mode, the -i option is used to specify the search path for source files, whereas in standard batch-compilation mode the -i option is used to specify the search path for interface files.

2
haskellghcghci

2 Answers

2
votes

The '-i' flag is fine, the problem is with loading the module.

Within ghci, :m will only switch to either pre-compiled modules, or modules which were specified on the command-line. You need to use :add MyModule to tell ghci to compile a Haskell source file.

If you have

./src/Module/SubModule.hs

you can load it with the following:

localuser$ ghci -isrc
GHCi, version 7.0.3: http://www.haskell.org/ghc/  :? for help
Loading package ghc-prim ... linking ... done.
Loading package integer-gmp ... linking ... done.
Loading package base ... linking ... done.
Loading package ffi-1.0 ... linking ... done.
Prelude> :add Module.SubModule
[1 of 1] Compiling Module.SubModule        ( src/Module/SubModule.hs, interpreted )
Ok, modules loaded: Module.SubModule.
*Module.SubModule>
0
votes

I think you can say :set -i /d/haskell/src; many, but not all, GHC options can be set that way. Alternatively, you should be able to use it as a parameter directly: ghci -i /d/haskell/src.