MD5 is 128 bits but why is it 32 characters?

Question

I read some docs about md5, it said that its 128 bits, but why is it 32 characters? I can't compute the characters.

• 1 byte is 8 bits
• if 1 character is 1 byte
• then 128 bits is 128/8 = 16 bytes right?

EDIT:

SHA-1 produces 160 bits, so how many characters are there?

Answer 1

32 chars as hexdecimal representation, thats 2 chars per byte.

Answer 2

I wanted summerize some of the answers into one post.

First, don't think of the MD5 hash as a character string but as a hex number. Therefore, each digit is a hex digit (0-15 or 0-F) and represents four bits, not eight.

Taking that further, one byte or eight bits are represented by two hex digits, e.g. b'1111 1111' = 0xFF = 255.

MD5 hashes are 128 bits in length and generally represented by 32 hex digits.

SHA-1 hashes are 160 bits in length and generally represented by 40 hex digits.

For the SHA-2 family, I think the hash length can be one of a pre-determined set. So SHA-512 can be represented by 128 hex digits.

Again, this post is just based on previous answers.

Answer 3

A hex "character" (nibble) is different from a "character"

To be clear on the bits vs byte, vs characters.

• 1 byte is 8 bits (for our purposes)
• 8 bits provides 2**8 possible combinations: 256 combinations

When you look at a hex character,

• 16 combinations of [0-9] + [a-f]: the full range of 0,1,2,3,4,5,6,7,8,9,a,b,c,d,e,f
• 16 is less than 256, so one one hex character does not store a byte.
• 16 is 2**4: that means one hex character can store 4 bits in a byte (half a byte).
• Therefore, two hex characters, can store 8 bits, 2**8 combinations.
• A byte represented as a hex character is [0-9a-f][0-9a-f] and that represents both halfs of a byte (we call a half-byte a nibble).

When you look at a regular single-byte character, (we're totally going to skip multi-byte and wide-characters here)

• It can store far more than 16 combinations.
• The capabilities of the character are determined by the encoding. For instance, the ISO 8859-1 that stores an entire byte, stores all this stuff
• All that stuff takes the entire 2**8 range.
• If a hex-character in an md5() could store all that, you'd see all the lowercase letters, all the uppercase letters, all the punctuation and things like ¡°ÀÐàð, whitespace like (newlines, and tabs), and control characters (which you can't even see and many of which aren't in use).

So they're clearly different and I hope that provides the best break down of the differences.

Answer 4

MD5 yields hexadecimal digits (0-15 / 0-F), so they are four bits each. 128 / 4 = 32 characters.

SHA-1 yields hexadecimal digits too (0-15 / 0-F), so 160 / 4 = 40 characters.

(Since they're mathematical operations, most hashing functions' output is commonly represented as hex digits.)

You were probably thinking of ASCII text characters, which are 8 bits.

Answer 5

That's 32 hex characters - 1 hex character is 4 bits.

Answer 6

One hex digit = 1 nibble (four-bits)

Two hex digits = 1 byte (eight-bits)

MD5 = 32 hex digits

32 hex digits = 16 bytes ( 32 / 2)

16 bytes = 128 bits (16 * 8)

The same applies to SHA-1 except it's 40 hex digits long.

I hope this helps.

Answer 7

Those are hexidecimal digits, not characters. One digit = 4 bits.

Answer 8

They're not actually characters, they're hexadecimal digits.

Answer 9

For clear understanding, copy the MD5 calculated 128 bit hash value in the Binary to Hex convertor and see the length of the Hex value. You will get 32 characters Hex characters.