I want to extract the digits from a string that contains numbers and letters like:
"In My Cart : 11 items"
I want to extract the number 11
.
If you just want to filter everything other than the numbers out, the easiest is to use filter_var:
$str = 'In My Cart : 11 items';
$int = (int) filter_var($str, FILTER_SANITIZE_NUMBER_INT);
I do not own the credit for this, but I just have to share it. This regex will get numbers from a string, including decimal points/places, as well as commas:
/((?:[0-9]+,)*[0-9]+(?:\.[0-9]+)?)/
Cited from here:
php - regex - how to extract a number with decimal (dot and comma) from a string (e.g. 1,120.01)?
Using preg_replace
$str = 'In My Cart : 11 12 items';
$str = preg_replace('/\D/', '', $str);
echo $str;
preg_match_all('!\d+!', $some_string, $matches);
$string_of_numbers = implode(' ', $matches[0]);
The first argument in implode in this specific case says "separate each element in matches[0] with a single space." Implode will not put a space (or whatever your first argument is) before the first number or after the last number.
Something else to note is $matches[0] is where the array of matches (that match this regular expression) found are stored.
For further clarification on what the other indexes in the array are for see: http://php.net/manual/en/function.preg-match-all.php
try this,use preg_replace
$string = "Hello! 123 test this? 456. done? 100%";
$int = intval(preg_replace('/[^0-9]+/', '', $string), 10);
echo $int;
we can extract int from it like
$string = 'In My Car_Price : 50660.00';
echo intval(preg_replace('/[^0-9.]/','',$string)); # without number format output: 50660
echo number_format(intval(preg_replace('/[^0-9.]/','',$string))); # with number format output :50,660
demo : http://sandbox.onlinephpfunctions.com/code/82d58b5983e85a0022a99882c7d0de90825aa398
Follow this step it will convert string to number
$value = '$0025.123';
$onlyNumeric = filter_var($value, FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION);
settype($onlyNumeric,"float");
$result=($onlyNumeric+100);
echo $result;
Another way to do it :
$res = preg_replace("/[^0-9.]/", "", "$15645623.095605659");
Since there is only 1 numeric value to isolate in your string, I would endorse and personally use filter_var()
with FILTER_SANITIZE_NUMBER_INT
.
echo filter_var($string, FILTER_SANITIZE_NUMBER_INT);
A whackier technique which works because there is only 1 numeric value AND the only characters that come before the integer are alphanumeric, colon, or spaces is to use ltrim()
with a character mask then cast the remaining string as an integer.
$string = "In My Cart : 11 items";
echo (int)ltrim($string, 'A..z: ');
// 11
If for some reason there was more than one integer value and you wanted to grab the first one, then regex would be a direct technique.
echo preg_match('/\d+/', $string, $m) ? $m[0] : '';
other way(unicode string even):
$res = array();
$str = 'test 1234 555 2.7 string ..... 2.2 3.3';
$str = preg_replace("/[^0-9\.]/", " ", $str);
$str = trim(preg_replace('/\s+/u', ' ', $str));
$arr = explode(' ', $str);
for ($i = 0; $i < count($arr); $i++) {
if (is_numeric($arr[$i])) {
$res[] = $arr[$i];
}
}
print_r($res); //Array ( [0] => 1234 [1] => 555 [2] => 2.7 [3] => 2.2 [4] => 3.3 )
This script creates a file at first , write numbers to a line and changes to a next line if gets a character other than number. At last, again it sorts out the numbers to a list.
string1 = "hello my name 12 is after 198765436281094and14 and 124de"
f= open("created_file.txt","w+")
for a in string1:
if a in ['1','2','3','4','5','6','7','8','9','0']:
f.write(a)
else:
f.write("\n" +a+ "\n")
f.close()
#desired_numbers=[x for x in open("created_file.txt")]
#print(desired_numbers)
k=open("created_file.txt","r")
desired_numbers=[]
for x in k:
l=x.rstrip()
print(len(l))
if len(l)==15:
desired_numbers.append(l)
#desired_numbers=[x for x in k if len(x)==16]
print(desired_numbers)