COUNTIFS formula - unique values

Question

I would like to create one formula that will give me the desired result, which is number of unique IDs with "0" Amount. Below I have two formulas, but since the whole document has a lot of data, I would like to have one formula.

first formula counts how many times ID occurs in column A =COUNTIFS($A$2:$A2,A2,$G$2:$G2,"0")

second formula counts how many unique IDs have "0" Amount in column G =COUNTIFS(K2:K18,"1",G2:G18,"0")

sample of raw data:

ID      Amount
100075738   0
100075738   0
27258   312.76
27300   961.59
27372   316.96
27578   769.3
30609   0
33163   573.16
36245   0
36249   3365.6
42026   1563.8
47065   673.12
48966   442.33
100007640   1287.16
100010436   2615.55
100026622   692.44
100028235   1548.4

urdearboy urdearboy · Accepted Answer · 2020-04-28T17:06:14

If you have access to the new Dynamic Array formulas in excel you can use:

=COUNT(UNIQUE(FILTER(A2:A18,B2:B18=0)))

If you don't have access to those, you can use this Array formula instead
(Must be confirmed with CTRL + SHIFT + ENTER )

=SUM(--(FREQUENCY(IF(B2:B18=0,MATCH(A2:A18,A2:A18,0)),ROW(A2:A18)-ROW(A2)+1)>0))

Output of both are below in photo along with formula used next to output for reference

COUNTIFS formula - unique values

1 Answers