I've got a bunch of documents with disparate styles that I've been adding to a long Macro that finds and replaces these styles with the correct ones. Right now, I'm just adding to a list as I find a wrong style. For example, there can be Heading 1, heading 1, H1, or h1. I want to write a find and replace function for each of those for the moment. What would be cooler is if I could write a catch all macro for these sorts of things using Regex: (h|H).{6}\s1 (not the best Regex writer, so bear with that). Ideally that would catch anything the variations of heading 1 (though it would not catch the h1, H1 cases, though I could add that easily enough.
I know that VBA supports Regex. I've added the reference to it. I also know how this would work for replacing specific text. I'm not replacing text though. ONLY formatting. I haven't played around with it too much. I just want to know if I can use the Regex when working specifically with a style. Here's what the functions look like right now:
Selection.Find.ClearFormatting
Selection.Find.Style = ActiveDocument.Styles("Heading 1")
Selection.Find.Replacement.ClearFormatting
Selection.Find.Replacement.Style = ActiveDocument.Styles("SSC TOC 2")
With Selection.Find
.Text = ""
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
I simply recorded that. Now, would I be able to put Regex in place of that string, like so:
Selection.Find.ClearFormatting
Selection.Find.Style = ActiveDocument.Styles(someRegex function (h|H).{6}\s1)
Selection.Find.Replacement.ClearFormatting
Selection.Find.Replacement.Style = ActiveDocument.Styles("SSC TOC 2")
With Selection.Find
.Text = ""
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
Basically just using a function someRegex function (h|H).{6}\s1 in place of the string literal. Is there any way to do this? Would appreciate any guidance or help!