Rust deserialize json based on an enum in the json

Question

Is it possible to use a value in JSON to determine how to deserialize the rest of the JSON using serde? For example, consider the following code:

use serde::{Serialize, Deserialize};
use serde_repr::*;

#[derive(Serialize_repr, Deserialize_repr, Debug)]
#[repr(u8)]
enum StructType {
    Foo = 1,
    Bar = 2
}

#[derive(Serialize, Deserialize, Debug)]
struct Foo {
    a: String,
    b: u8
}

#[derive(Serialize, Deserialize, Debug)]
struct Bar {
    x: String,
    y: u32,
    z: u16
}

#[derive(Serialize, Deserialize, Debug)]
struct AllMyStuff {
    type: StructType,
    data: //HELP: Not sure what to put here
}

What I'm trying to achieve is deserialization of the data, even if in multiple steps, where the type field in the AllMyStuff determines which type of struct data is present in data. For example, given the following pseudocode, I'd like to ultimately have a Bar struct with the proper data in it:

data = {"type": "2", "data": { "x": "Hello world", "y": "18", "z": "5" } }
// 1) use serde_json to deserialize a AllMyStuff struct, not erroring on the "data" blob
// 2) Now that we know data is of type "2" (or Bar), parse the remaining "data" into a AllMyStuff struct

If steps (1) and (2) are somehow able to be done in a single step, that would be awesome but not needed. I'm not sure what type of type to declare data in the AllMyStuff struct to enable this as well.

phimuemue phimuemue · Accepted Answer · 2020-02-27T22:34:44

I may be missing something, but AllMyStuff looks as if you are trying to manually distinguish between Foo and Bar.

However, Rust, has a built-in way of doing this:

#[derive(Serialize, Deserialize, Debug)]
enum AllMyStuff {
    Foo(Foo),
    Bar(Bar),
}

Click here to see it in action.

Rust deserialize json based on an enum in the json

2 Answers