Spring security error Circular view path [index]: would dispatch back to the current handler URL [/index] again. Check your ViewResolver setup

Question

I am getting following error while running spring boot security app with gradle -

javax.servlet.ServletException: Circular view path [index]: would dispatch back to the current handler URL [/index] again. Check your ViewResolver setup! (Hint: This may be the result of an unspecified view, due to default view name generation.) at org.springframework.web.servlet.view.InternalResourceView.prepareForRendering(InternalResourceView.java:210) [spring-webmvc-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.web.servlet.view.InternalResourceView.renderMergedOutputModel(InternalResourceView.java:148) [spring-webmvc-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.web.servlet.view.AbstractView.render(AbstractView.java:316) [spring-webmvc-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.web.servlet.DispatcherServlet.render(DispatcherServlet.java:1373) [spring-webmvc-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.web.servlet.DispatcherServlet.processDispatchResult(DispatcherServlet.java:1118) [spring-webmvc-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:1057) [spring-webmvc-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:943) [spring-webmvc-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:1006) [spring-webmvc-5.2.2.RELEASE.jar:5.2.2.RELEASE] at org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:898) [spring-webmvc-5.2.2.RELEASE.jar:5.2.2.RELEASE] at javax.servlet.http.HttpServlet.service(HttpServlet.java:634) [tomcat-embed-core-9.0.29.jar:9.0.29] at org.springframework.web.servlet.FrameworkServlet.service(FrameworkServlet.java:883) [spring-webmvc-5.2.2.RELEASE.jar:5.2.2.RELEASE] at javax.servlet.http.HttpServlet.service(HttpServlet.java:741) [tomcat-embed-core-9.0.29.jar:9.0.29]

I have added following code in application -

src/main/resources/templates/index.html

<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml" xmlns:th="https://www.thymeleaf.org" xmlns:sec="https://www.thymeleaf.org/thymeleaf-extras-springsecurity3">
    <head>
        <title>Spring Security Example</title>
    </head>
    <body>
        <h1>Welcome!</h1>

        <p>Click <a th:href="@{/main}">here</a> to see a greeting.</p>
    </body>
</html>

src/main/resources/templates/main.html

<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml" xmlns:th="https://www.thymeleaf.org"
      xmlns:sec="https://www.thymeleaf.org/thymeleaf-extras-springsecurity3">
    <head>
        <title>Hello World!</title>
    </head>
    <body>
        <h1>Hello world!</h1>
    </body>
</html>

src/main/resources/templates/mylogin.html

<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml" xmlns:th="https://www.thymeleaf.org"
      xmlns:sec="https://www.thymeleaf.org/thymeleaf-extras-springsecurity3">
    <head>
        <title>Spring Security Example </title>
    </head>
    <body>
        <div th:if="${param.error}">
            Invalid username and password.
        </div>
        <div th:if="${param.logout}">
            You have been logged out.
        </div>
        <form th:action="@{/mylogin}" method="post">
            <div><label> User Name : <input type="text" name="username"/> </label></div>
            <div><label> Password: <input type="password" name="password"/> </label></div>
            <div><input type="submit" value="Sign In"/></div>
        </form>
    </body>
</html>

src/main/com/example/security/MVCConfig.java

package com.example.security;

import org.springframework.context.annotation.Configuration;
import org.springframework.web.servlet.config.annotation.ViewControllerRegistry;
import org.springframework.web.servlet.config.annotation.WebMvcConfigurer;

@Configuration
public class MVCConfig implements WebMvcConfigurer {

  public void addViewControllers(ViewControllerRegistry registry) {
    registry.addViewController("/index").setViewName("index");
    registry.addViewController("/").setViewName("index");
    registry.addViewController("/main").setViewName("main");
    registry.addViewController("/mylogin").setViewName("mylogin");
  }
}

src/main/com/example/security/WebSecurityConfig.java


package com.example.security;

import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.security.config.annotation.web.builders.HttpSecurity;
import org.springframework.security.config.annotation.web.configuration.EnableWebSecurity;
import org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter;
import org.springframework.security.core.userdetails.User;
import org.springframework.security.core.userdetails.UserDetails;
import org.springframework.security.core.userdetails.UserDetailsService;
import org.springframework.security.provisioning.InMemoryUserDetailsManager;

@Configuration
@EnableWebSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {
  @Override
  protected void configure(HttpSecurity http) throws Exception {
    http
      .authorizeRequests()
        .antMatchers("/", "/main").permitAll()
        .anyRequest().authenticated()
        .and()
      .formLogin()
        .loginPage("/mylogin")
        .permitAll()
        .and()
      .logout()
        .permitAll();
  }

  @Bean
  @Override
  public UserDetailsService userDetailsService() {
    UserDetails user =
       User.withDefaultPasswordEncoder()
        .username("user")
        .password("password")
        .roles("USER")
        .build();

    return new InMemoryUserDetailsManager(user);
  }
}

src/main/com/example/security/SecurityApplication.java


package com.example.security;

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;

@SpringBootApplication
public class SecurityApplication {

    public static void main(String[] args) {
        SpringApplication.run(SecurityApplication.class, args);
    }

}

build.gradle

plugins {
    id 'org.springframework.boot' version '2.2.2.RELEASE'
    id 'io.spring.dependency-management' version '1.0.8.RELEASE'
    id 'java'
}

group = 'com.example'
version = '0.0.1-SNAPSHOT'
sourceCompatibility = '1.8'

repositories {
    mavenCentral()
}

dependencies {
    implementation 'org.springframework.boot:spring-boot-starter-security'
    implementation 'org.springframework.boot:spring-boot-starter-web'   
    testImplementation('org.springframework.boot:spring-boot-starter-test') {
        exclude group: 'org.junit.vintage', module: 'junit-vintage-engine'
    }
    testImplementation 'org.springframework.security:spring-security-test'
}

test {
    useJUnitPlatform()
}

özkan pakdil özkan pakdil · Accepted Answer · 2019-12-24T12:16:17

You forget one dependency. please add

implementation 'org.springframework.boot:spring-boot-starter-thymeleaf'

to your dependencies.

you can see running example here https://github.com/ozkanpakdil/spring-examples/tree/master/gradle-thymeleaf

Spring security error Circular view path [index]: would dispatch back to the current handler URL [/index] again. Check your ViewResolver setup

1 Answers