I want to create a recursive descendant parser in java for following grammar (I have managed to create tokens). This is the relevant part of the grammar:
expression ::= numeric_expression | identifier | "null"
identifier ::= "a..z,$,_"
numeric_expression ::= ( ( "-" | "++" | "--" ) expression )
| ( expression ( "++" | "--" ) )
| ( expression ( "+" | "+=" | "-" | "-=" | "*" | "*=" | "/" | "/=" | "%" | "%=" ) expression )
arglist ::= expression { "," expression }
I have written code for parsing numeric_expression (assuming if invalid token, return null):
NumericAST<? extends OpAST> parseNumericExpr() {
OpAST op;
if (token.getCodes() == Lexer.CODES.UNARY_OP) { //Check for unary operator like "++" or "--" etc
op = new UnaryOpAST(token.getValue());
token = getNextToken();
AST expr = parseExpr(); // Method that returns expression node.
if (expr == null) {
op = null;
return null;
} else {
if (checkSemi()) {
System.out.println("UNARY AST CREATED");
return new NumericAST<OpAST>(expr, op, false);
}
else {
return null;
}
}
} else { // Binary operation like "a+b", where a,b ->expression
AST expr = parseExpr();
if (expr == null) {
return null;
} else {
token = getNextToken();
if (token.getCodes() == Lexer.CODES.UNARY_OP) {
op = new UnaryOpAST(token.getValue());
return new NumericAST<OpAST>(expr, op, true);
} else if (token.getCodes() == Lexer.CODES.BIN_OP) {
op = new BinaryOpAST(token.getValue());
token = getNextToken();
AST expr2 = parseExpr();
if (expr2 == null) {
op = null;
expr = null;
return null;
} else {
if (checkSemi()) {
System.out.println("BINARY AST CREATED");
return new NumericAST<OpAST>(expr, op, expr2);
}
else {
return null;
}
}
} else {
expr = null;
return null;
}
}
}
}
Now, if i get a unary operator like ++ i can directly call this method, but I dont know to recognize other grammar, starting with same productions, like arglist and numeric_expression having "expression" as start production.
My question is:
How to recognize whether to call parseNumericExpr() or parseArgList() (method not mentioned above) if i get an expression token?
UnaryOperatorASTin your code, but unary operator expression does not seem to be a building block in your grammar. - Paul Benn