when compile protocol buffer, missing input or program is not executable error

Question

I'm trying to make golang+grpc server on mac. I installed golang, grpc, protocol buffer and checked that grpc server following this example https://grpc.io/docs/quickstart/go/ The problem is when I try to compile .proto file using protocol buffer it said 'missing input' or 'program is not executable'.

install protocol buffer and grpc

brew install grpc protobuf

install golang based protoc plugin

go get github.com/golang/protobuf/protoc-gen-go

protoc path

which protoc
/usr/local/bin/protoc

example location

/Users/usrname/go/src/google.golang.org/grpc/examples/helloworld

run proto compiler

protoc -I=/Users/username/go/src/google.golang.org/grpc/examples/helloworld/helloworld/ --go_out=/Users/username/go/src/google.golang.org/grpc/examples/helloworld/helloworld/ /Users/username/go/src/google.golang.org/grpc/examples/helloworld/helloworld/helloworld.proto

error message

protoc-gen-go: program not found or is not executable
Please specify a program using absolute path or make sure the program is available in your PATH system variable
--go_out: protoc-gen-go: Plugin failed with status code 1.

VonC VonC · Accepted Answer · 2019-10-04T04:28:25

This was mentioned in golang/protobuf issue 795

See the Installation section of the page README:

Grab the code from the repository and install the proto package.
The simplest way is to run go get -u github.com/golang/protobuf/protoc-gen-go.

The compiler plugin, protoc-gen-go, will be installed in $GOPATH/bin unless $GOBIN is set. It must be in your $PATH for the protocol compiler, protoc, to find it.

So double-check the value of your $GOPATH (~/go by default if not set)

If $GOPATH/bin (or ~/go/bin) in your $PATH?

The OP camilla confirms it is not:

$PATH also has :/Users/username/go/bin/protoc-gen-go

It should have :/Users/username/go/bin

when compile protocol buffer, missing input or program is not executable error

1 Answers