I have reproduced my problem in the short code below.
Problem: The inner thread
uses reference of variable v
from the outer thread
. The rust compiler throws an error because "technically" the outer thread
could terminate before the inner thread
and hence inner thread
could loose access to variable v
. However in the code below that clearly cannot happen.
Question: How shall I change this code so that it complies while maintaining the same functionality?
fn main() { //outer thread
let v = vec![0, 1];
let test = Test { v: &v }; //inner_thread
std::thread::spawn(move || test.print());
loop {
// this thread will never die because it will never leave this loop
}
}
pub struct Test<'a> {
v: &'a Vec<u32>,
}
impl<'a> Test<'a> {
fn print(&self) {
println!("{:?}", self.v);
}
}
error[E0597]: `v` does not live long enough
--> src/main.rs:3:26
|
3 | let test = Test { v: &v }; //inner_thread
| ^^ borrowed value does not live long enough
4 | std::thread::spawn(move || test.print());
| ---------------------------------------- argument requires that `v` is borrowed for `'static`
...
8 | }
| - `v` dropped here while still borrowed