Controlling after Speech Recognition

Question

How to trigger commands after speech to text conversion? Now i have text but unable to compare it using if condition in python so I can perform my required task.I have used pocketsphinx for speech recognition in raspberry pi.

   import os
   from pocketsphinx import LiveSpeech, get_model_path

   model_path = get_model_path()

   speech = LiveSpeech(
        verbose=False,
        sampling_rate=16000,
        buffer_size=2048,
        no_search=False,
        full_utt=False,
        hmm=os.path.join(model_path, 'en-us'),
        lm=os.path.join(model_path, 'en-us.lm.bin'),
        dic=os.path.join(model_path, 'cmudict-en-us.dict')
    )

    for phrase in speech:
       print(phrase)
       if phrase == "HOME"
           print (OK)

Code doesn't give any error and work fine; what i say it prints on the screen i.e. Code works till last 3rd line [print (phrase)] and give expected results but last 2 line doesn't perform required task but give no error

What is it prints exactly? Code looks correct except of value of OK (is it variable or you mean 'OK'?), maybe you must take account of case (phrase.lower() == 'home') or check not for exact equality ('home' in phrase.lower(), phrase.lower().startswith('home')) — Sav
Thanks for your consideration; I have attached the result, and i have consider the CASES of word "HOME", whereas by OK i meant a word "OK" not a variable — Hassaan Khan
looking into documentation I've seen what phrase isn't a string. change print(phrase) to print(phrase, type(phrase), dir(phrase)) and show the result, it may hint how to compare it or get a string from it — Sav
Really appreciate your answer; u r right that it's not a string ;when i print (type(phrase)) it shows[<class 'pocketsphinx.LiveSpeech'>] Could u guide me how to compare class and string ; Since I am a NOOB in programming , when i type [dir(phrase)] it shows number of complex directories. — Hassaan Khan

Nikolay Shmyrev Nikolay Shmyrev · Accepted Answer · 2019-06-28T22:34:14

0

votes

You can use

if str(phrase) == "HOME":

or

if phrase.hypothesis() == "HOME":

Controlling after Speech Recognition

1 Answers