948
votes

I try to check a radio button with jQuery. Here's my code:

<form>
    <div id='type'>
        <input type='radio' id='radio_1' name='type' value='1' />
        <input type='radio' id='radio_2' name='type' value='2' />
        <input type='radio' id='radio_3' name='type' value='3' /> 
    </div>
</form>

And the JavaScript:

jQuery("#radio_1").attr('checked', true);

Doesn't work:

jQuery("input[value='1']").attr('checked', true);

Doesn't work:

jQuery('input:radio[name="type"]').filter('[value="1"]').attr('checked', true);

Doesn't work:

Do you have another idea? What am I missing?

30
Thanks for your responses! I found the problem. Actually, the two first ways to do it are working. The point is I used jqueryUI to transform a set of 3 radio buttons into a button set with this code : jQuery("#type").buttonset(); but making this change before checking the radio was breaking the radio set (don't know why). Finally, I put the buttonset call after checking the radio and it works impeccably.Alexis

30 Answers

1562
votes

For versions of jQuery equal or above (>=) 1.6, use:

$("#radio_1").prop("checked", true);

For versions prior to (<) 1.6, use:

$("#radio_1").attr('checked', 'checked');

Tip: You may also want to call click() or change() on the radio button afterwards. See comments for more info.

271
votes

Try this.

In this example, I'm targeting it with its input name and value

$("input[name=background][value='some value']").prop("checked",true);

Good to know: in case of multi-word value, it will work because of apostrophes, too.

95
votes

One more function prop() that is added in jQuery 1.6, that serves the same purpose.

$("#radio_1").prop("checked", true); 
92
votes

Short and easy to read option:

$("#radio_1").is(":checked")

It returns true or false, so you can use it in "if" statement.

33
votes

Try this.

To check Radio button using Value use this.

$('input[name=type][value=2]').attr('checked', true); 

Or

$('input[name=type][value=2]').attr('checked', 'checked');

Or

$('input[name=type][value=2]').prop('checked', 'checked');

To check Radio button using ID use this.

$('#radio_1').attr('checked','checked');

Or

$('#radio_1').prop('checked','checked');
16
votes

Try This:

$("input[name=type]").val(['1']);

http://jsfiddle.net/nwo706xw/

14
votes

The $.prop way is better:

$(document).ready(function () {                            
    $("#radio_1").prop('checked', true);        
});

and you can test it like the following:

$(document).ready(function () {                            
    $("#radio_1, #radio_2", "#radio_3").change(function () {
        if ($("#radio_1").is(":checked")) {
            $('#div1').show();
        }
        else if ($("#radio_2").is(":checked")) {
            $('#div2').show();
        }
        else 
            $('#div3').show();
    });        
});
10
votes

Surprisingly, the most popular and accepted answer ignores triggering appropriate event despite of the comments. Make sure you invoke .change(), otherwise all the "on change" bindings will ignore this event.

$("#radio_1").prop("checked", true).change();
10
votes

Use prop() mehtod

enter image description here

Source Link

<p>
    <h5>Radio Selection</h5>

    <label>
        <input type="radio" name="myRadio" value="1"> Option 1
    </label>
    <label>
        <input type="radio" name="myRadio" value="2"> Option 2
    </label>
    <label>
        <input type="radio" name="myRadio" value="3"> Option 3
    </label>
</p>

<p>
    <button>Check Radio Option 2</button>
</p>


<script>
    $(function () {

        $("button").click(function () {
            $("input:radio[value='2']").prop('checked',true);
        });

    });
</script>
9
votes

You have to do

jQuery("#radio_1").attr('checked', 'checked');

That's the HTML attribute

7
votes

If property name does not work don't forget that id still exists. This answer is for people who wants to target the id here how you do.

$('input[id=element_id][value=element_value]').prop("checked",true);

Because property name does not work for me. Make sure you don't surround id and name with double/single quotations.

Cheers!

7
votes

We should want to tell it is a radio button.So please try with following code.

$("input[type='radio'][name='userRadionButtonName']").prop('checked', true);
7
votes

Yes, it worked for me like a way:

$("#radio_1").attr('checked', 'checked');
6
votes

Try this

$(document).ready(function(){
    $("input[name='type']:radio").change(function(){
        if($(this).val() == '1')
        {
          // do something
        }
        else if($(this).val() == '2')
        {
          // do something
        }
        else if($(this).val() == '3')
        {
          // do something
        }
    });
});
5
votes
$("input[name=inputname]:radio").click(function() {
    if($(this).attr("value")=="yes") {
        $(".inputclassname").show();
    }
    if($(this).attr("value")=="no") {
        $(".inputclassname").hide();
    }
});
5
votes

Get value:

$("[name='type'][checked]").attr("value");

Set value:

$(this).attr({"checked":true}).prop({"checked":true});

Radio Button click add attr checked:

$("[name='type']").click(function(){
  $("[name='type']").removeAttr("checked");
  $(this).attr({"checked":true}).prop({"checked":true});
});
5
votes

Try this with example

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="myForm">
<input type="radio" name="radio" value="first"/> 1 <br/>
<input type="radio" name="radio" value="second"/> 2 <br/>
</form>


<script>
$(document).ready(function () {
    $('#myForm').on('click', function () {
        var value = $("[name=radio]:checked").val();

        alert(value);
    })
});
</script>
5
votes

Just in case anyone is trying to achieve this while using jQuery UI, you will also need to refresh the UI checkbox object to reflect the updated value:

$("#option2").prop("checked", true); // Check id option2
$("input[name='radio_options']").button("refresh"); // Refresh button set
4
votes

I use this code:

I'm sorry for English.

var $j = jQuery.noConflict();

$j(function() {
    // add handler
    $j('#radio-1, #radio-2').click(function(){

        // find all checked and cancel checked
        $j('input:radio:checked').prop('checked', false);

        // this radio add cheked
        $j(this).prop('checked', true);
    });
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<fieldset class="section">
  <legend>Radio buttons</legend>
  <label>
    <input type="radio" id="radio-1" checked>
    Option one is this and that&mdash;be sure to include why it's great
  </label>
  <br>
  <label>
    <input type="radio" id="radio-2">
    Option two can be something else
  </label>
</fieldset>
3
votes

Try this

var isChecked = $("#radio_1")[0].checked;
3
votes
function rbcitiSelction(e) {
     debugger
    $('#trpersonalemail').hide();
    $('#trcitiemail').show();
}

function rbpersSelction(e) {
    var personalEmail = $(e).val();
    $('#trpersonalemail').show();
    $('#trcitiemail').hide();
}

$(function() {  
    $("#citiEmail").prop("checked", true)
});
2
votes
$("#radio_1").attr('checked', true);
//or
$("#radio_1").attr('checked', 'checked');
2
votes

I got some related example to be enhanced, how about if I want to add a new condition, lets say, if I want colour scheme to be hidden after I click on project Status value except Pavers and Paving Slabs.

Example is in here:

$(function () {
    $('#CostAnalysis input[type=radio]').click(function () {
        var value = $(this).val();

        if (value == "Supply & Lay") {
            $('#ul-suplay').empty();
            $('#ul-suplay').append('<fieldset data-role="controlgroup"> \

http://jsfiddle.net/m7hg2p94/4/

2
votes

I've just have a similar problem, a simple solution is to just use:

.click()

Any other solution will work if you refresh radio after calling function.

2
votes

In addition, you can check if the element is checked or not:

if ($('.myCheckbox').attr('checked'))
{
   //do others stuff
}
else
{
   //do others stuff
}

You can checked for unchecked element:

$('.myCheckbox').attr('checked',true) //Standards way

You can also uncheck this way:

$('.myCheckbox').removeAttr('checked')

You can checked for radio button:

For versions of jQuery equal or above (>=) 1.6, use:

$("#radio_1").prop("checked", true);

For versions prior to (<) 1.6, use:

$("#radio_1").attr('checked', 'checked');
2
votes

I used jquery-1.11.3.js

Basic Enable & disable

Tips 1: (Radio button type common Disable & Enable)

$("input[type=radio]").attr('disabled', false);
$("input[type=radio]").attr('disabled', true); 

Tips 2: ( ID selector Using prop() or attr())

$("#paytmradio").prop("checked", true);
$("#sbiradio").prop("checked", false);

jQuery("#paytmradio").attr('checked', 'checked'); // or true this won't work
jQuery("#sbiradio").attr('checked', false);

Tips 3: ( Class selector Using prop() or arrt())

$(".paytm").prop("checked", true);
$(".sbi").prop("checked", false);

jQuery(".paytm").attr('checked', 'checked'); // or true
jQuery(".sbi").attr('checked', false);

OTHER TIPS

$("#paytmradio").is(":checked")   // Checking is checked or not
$(':radio:not(:checked)').attr('disabled', true); // All not check radio button disabled

$('input[name=payment_type][value=1]').attr('checked', 'checked'); //input type via checked
 $("input:checked", "#paytmradio").val() // get the checked value

index.html

<div class="col-md-6">      
    <label class="control-label" for="paymenttype">Payment Type <span style="color:red">*</span></label>
    <div id="paymenttype" class="form-group" style="padding-top: inherit;">
        <label class="radio-inline" class="form-control"><input  type="radio" id="paytmradio"  class="paytm" name="paymenttype" value="1" onclick="document.getElementById('paymentFrm').action='paytmTest.php';">PayTM</label>
        <label class="radio-inline" class="form-control"><input  type="radio" id="sbiradio" class="sbi" name="paymenttype" value="2" onclick="document.getElementById('paymentFrm').action='sbiTest.php';">SBI ePAY</label>
    </div>
</div>
2
votes

This answer is thanks to Paul LeBeau in a comment. I thought I'd write it up as a proper answer since there surprisingly wasn't one.

The only thing that worked for me (jQuery 1.12.4, Chrome 86) was:

$(".js-my-radio-button").trigger("click");

This does everything I want – changes which radio button looks selected (both visually and programmatically) and triggers events such as change on the radio button.

Just setting the "checked" attribute as other answers suggest would not change which radio button was selected for me.

1
votes

try this

 $("input:checked", "#radioButton").val()

if checked returns True if not checked returns False

jQuery v1.10.1
1
votes

Some times above solutions do not work, then you can try below:

jQuery.uniform.update(jQuery("#yourElementID").attr('checked',true));
jQuery.uniform.update(jQuery("#yourElementID").attr('checked',false));

Another way you can try is:

jQuery("input:radio[name=yourElementName]:nth(0)").attr('checked',true);
1
votes

Try This:

$(document).ready(function(){
  $("#Id").prop("checked", true).checkboxradio('refresh');
});