Transformation From One XML to Another XML Format Using JAXB in Apache Camel Route without using XSLT

Question

I have request xml which is consumed by target system. Target system accpets XML but format is different.So I need to build marshal and unmarshal logic to get data flowing in my route to Target System. So is there any way where I can achive using Java bean approach or jAXB without using dozer or XSLT

Apache Camel with Springboot

I guess you could have two classes with the relevant JAXB annotations SourceClass and TargetClass, and map the data from one class to another as a SourceClass method such as TargetClass sourceObject.toTargetClass(), or define a class that implements TypeConverters interface and register it in the Camel Context. However, if I'm mapping XML to XML I'd always use XSLT2 as it is very flexible and economical with code. — Screwtape
XSLT will be easier and more flexible than using pojo to pojo mapping — Namphibian
@Screwtape Thanks !!!Could you please provide any example for same — Singh Amita

Screwtape Screwtape · Accepted Answer · 2019-06-19T12:18:52

Here is a very quick and simple way to do an XSLT transformation.

Assuming your source data looks like this:

<?xml version="1.0"?>
<root>
  <elem1 id="1">
    <child1>Hello</child1>
    <child2>World</child2>
  </elem1>
</root>

you can have a transform XSLT file that looks a bit like:

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
  <xsl:output method="xml" indent="yes" />
  <xsl:template match="elem1">
    <div>
      <h1>Section <xsl:value-of select="@id" /></h1>
      <p><xsl:value-of select="child1" /></p>
      <p><xsl:value-of select="child2" /></p>
    </div>
  </xsl:template>
  <xsl:template match="@*|node()"> <!-- identity transform -->
    <xsl:copy>
        <xsl:apply-templates select="@*"/>
        <xsl:apply-templates select="node()"/>
    </xsl:copy>
  </xsl:template>
</xsl:stylesheet>

so you then pass this via the camel xslt transform, one way or another, for example

from("direct:start")
  .to("xslt:myTransformFile.xsl&saxon=true")
  .to("direct:end")

you should then end up with the following XML message being passed to direct:end:

<?xml version="1.0"?>
<root>
  <div>
    <h1>Section 1</h1>
    <p>Hello</p>
    <p>World</p>
  </div>
</root>

because the identity template has copied any elements that are not matched by another template, and the template replaces any element that match the selection criteria, with the contents of the template. In this case elem1 is replaced, by the contents of the template. The <xsl:value-of ... /> elements are interpreted but any element that doesn't begin <xsl:... is just part of the output.

For a simple introduction to XSLT, you can look here: https://www.w3schools.com/xml/xsl_intro.asp.

Transformation From One XML to Another XML Format Using JAXB in Apache Camel Route without using XSLT

1 Answers