When making a List with a row that pushes to a new view, SwiftUI adds a disclosure indicator ">" automatically? How do I remove it if I don't want it?
NavigationView {
List {
NavigationButton(destination: DetailView()) {
ListItem()
}
}
.navigationBarTitle(Text("Some title"))
}
On a UITableViewCell you set Accessory to None but how do I do that in SwiftUI?
Swift 5, Xcode 11. ZStack works perfect.
var body: some View {
NavigationView {
List {
ForEach(viewModel.currenciesViewModel) { cellViewModel in
ZStack {
cellViewModel.makeView()
NavigationLink(destination: ChooseCurrencyListView()) {
EmptyView()
}
.buttonStyle(PlainButtonStyle())
}
}
}
.navigationBarHidden(true)
.navigationBarTitle("", displayMode: .inline)
}
}
What you can do, if you are using list, is setting the navigationlink to hidden and its frame width to zero.
HStack{
Button(action: {self.statusShow = 1}, label: {
Image(systemName: "info.circle")
})
NavigationLink(destination: StimulatorSettingView(),
tag: 1,
selection: self.$statusShow){
EmptyView()
}.hidden().frame(width: 0)
}
This worked for me.
You don't have to use NavigationLink to wrap your Label directly. It will work as long as the link is anywhere in your view hierarchy.
Here I've wrapped it in a button, which allows you to trigger an action prior to pushing the view. Since the NavigationLink has an EmptyView for the label the disclosure indicator is not visible. You can also style this with ButtonStyle.
struct NavigationButton<Destination: View, Label: View>: View {
var action: () -> Void = { }
var destination: () -> Destination
var label: () -> Label
@State private var isActive: Bool = false
var body: some View {
Button(action: {
self.action()
self.isActive.toggle()
}) {
self.label()
.background(NavigationLink(destination: self.destination(), isActive: self.$isActive) {
EmptyView()
})
}
}
}
And to use it:
NavigationButton(
action: { print("tapped!") },
destination: { Text("Pushed View") },
label: { Text("Tap me") }
)
Works well for me!
import SwiftUI
struct LandmarkList: View {
var body: some View {
NavigationView {
List(landmarkData) { landmark in
LandmarkRow(landmark: landmark)
NavigationLink(destination: LandmarkDetail(landmark: landmark)) {
EmptyView()
}
}
.navigationBarTitle(Text("Landmarks"))
}
}
}
struct LandmarkList_Previews: PreviewProvider {
static var previews: some View {
ForEach(["iPhone SE", "iPhone 11 Pro Max"], id: \.self) { deviceName in
LandmarkList()
.previewDevice(PreviewDevice(rawValue: deviceName))
.previewDisplayName(deviceName)
}
}
}
NavigationLink is what we should define in a scope enclosed inside a NavigationView.
But when we use NavigationLink it is attached to the enclosing view, so to reuse the same NavigationLink with other views, we use tag which differentiates between different Destinations.
struct SwiftUIView: View {
@State private var viewState: Int? = 0
var body: some View {
NavigationView {
VStack {
NavigationLink(destination: Text("View 1"), tag: 1, selection: $viewState) {
EmptyView()
}
NavigationLink(destination: Text("View 2"), tag: 2, selection: $viewState) {
EmptyView()
}
Text("First View")
.onTapGesture {
self.viewState = 1
}
Text("Second View")
.onTapGesture {
self.viewState = 2
}
}
}
}
}
Here we bind a Hashable property with all the NavigationLinks present in our VStack so that when a particular View is tapped we can notify which Destination should be opened by setting the value of Bindable property.
If we don't notify the correct Destination by setting the value of tag, always the View defined inside the Closure of NavigationLink will be clickable and nothing else.
Using this approach you don't need to wrap all your clickable views inside NavigationView, any action on any view can use any NavigationLink just by setting the tag.
Thanks, hope this helps.
This helps to push and pass the model to the next navigation view controller.
struct ContentView : View {
@State var model = PostListViewModel()
var body: some View {
NavigationView {
List(model.post) { post in
ListCell(listData: post)
}.navigationBarTitle(Text("My Post"))
}
}
}
struct ListCell: View {
var listData: Post
var body: some View {
return NavigationButton(destination: DetailContentView(post: listData)) {
HStack {
ImageRow(model: listData) // Get image
VStack(alignment: .leading) {
Text(listData.login).font(.headline).lineLimit(nil)
Text(listData.url).font(.subheadline).lineLimit(nil)
}.padding(.leading, 10)
}.padding(.init(top: 5, leading: 0, bottom: 5, trailing: 0))
}
}
}
just came here looking for the answer to this question, but none of the proposed solutions worked for me (can't have an empty view, because i want to put something in the list row; i'm already messing with the padding (and increasing trailing padding didn't seem to work) ... i was about to give up, and then something occurred to me: what if you crank up the z-index of the list row itself? seemed somewhat unlikely, but i gave it a try and, i'll be damned, it worked! i was so pleasantly surprised, i felt like sharing ...
e.g.:
// in body of your list row view
HStack(alignment: .top, spacing: 0.0) {
// stuff ...
}
.zIndex(9999999999)
When using List() there is no way to remove disclosure indicator without workarounds. However there is another easy way to do want you want to do, without List(). Instead of a List(), you can use an ScrollView() which has a ForEach() in it.
It is neither harder nor more time-consuming, But it makes disclosure indicators of a NavigationLink disappear with no trick or workarounds, at no additional cost! letting you easily navigate to another view with a nice normal button.
If you need children behaviour for List and NavigationLink, without additional discloser in the same time, I want to promote this tricky solution, main point at HStack
var body: some View {
NavigationView {
List(items, children: \.items) { item in
ZStack {
NavigationLink(destination: DetailsView()) {
EmptyView()
}.hidden()
HStack {
RowView(item: item)
Spacer()
}
}
}
}
}
there is no documentation yet, so you can use ScrollView for now
NavigationView {
ScrollView {
ForEach(0...100){ x in
NavigationButton(destination: Text("ss")) {
HStack {
Text(String(x))
Spacer()
}
.padding()
.background(Color.white)
.shadow(radius:1,y:1)
}
}
.frame(width: UIScreen.main.bounds.width - 32)
.padding()
}
}
