I have an array that contains the local location of some images as shown below.
imagePath= ["file:///data/user/0/com.app.taamoutlet/cache/react-native-image-crop-picker/22536474236950.png","file:///data/user/0/com.app.taamoutlet/cache/react-native-image-crop-picker/22583225016770.png "]
I have done uploading for a single image. As per the code you have seen below I want to upload the images to firebase storage. I want to upload each image in the array to a single folder. And then collect the downloadable URL and each image and store that information under a single product as you see
() => {
const fs = RNFetchBlob.fs
const uid = "flyers/" + this.state.productUid;
const imageRef = firebase.storage().ref(uid).child(Math.random()+".jpg") //string "dp1.jpg"
let mime = 'image/jpg'
//------------------------------------------------
// coverting to base64
fs.readFile(this.state.imagePath, 'base64')
.then((data) => {
//console.log('data='+data);
return Blob.build(data, { type: `${mime};BASE64` })
})
.then((blob) => {
//uplaoding Image
uploadBlob = blob
return imageRef.put(blob, { contentType: mime })
})
.then(() => {
uploadBlob.close()
//getting url
return imageRef.getDownloadURL()
})
.then((url) => {
urls = url;
console.log('urls=' + urls)
//================================
try {
alert("Uploading Flyer" + this.state.title)
//-------------------------------------------
//----------Inserting Data to Database--------
usersTable = 'flyers/' + this.state.productUid,
console.log(usersTable)
firebase.database().ref(usersTable).set(
{
title: this.state.title,
description: this.state.description,
imageUrls: url,
storename: this.state.storename,
user: asyncValue,
longitude: this.state.longitude,
latitutde: this.state.latitutde
}
).then(
alert(this.state.title + " flyer sucessfully uploaded")
)
//--------------------------------------------
}
catch (error) {
this.setState({ loading: false })
this.setState({ disabled: false })
console.log(error.toString())
alert(error.toString())
}
//================================
})
}
Promise.all()
, see developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…. In each of yourthen()
s you have to manage the arrays of results returned byPromise.all()
and build a new array to pass to the nextPromise.all()
– Renaud Tarnec