Bot join and play file across all voice channels in a guild

Question

I've been making my first discord bot recently and today I'm facing an issue for a little requirement. I need my bot to connect to all voice channels of the server and play a mp3 file. It's for an alert message.

I first made a basic test with this code to play the mp3 in the channel the user who launch the command is connected :

exports.run = async (client, message, args, level) => {
  if (message.member.voiceChannel) {
    message.member.voiceChannel.join()
    .then(connection => {
        const dispatcher = connection.playFile('/home/pi/.discordbots/TARVIS/1.mp3');
        dispatcher.on("end", end => {message.member.voiceChannel.leave()});
    })
    .catch(console.error);
  }
};

The code above works fine

So I tried to make it for all voice channels :

  let voiceChannels = message.guild.channels.filter(channel => channel.type == 'voice');

  voiceChannels.forEach(channel =>
    channel.join()
      .then(connection => {
        const dispatcher = connection.playFile('/home/pi/.discordbots/TARVIS/1.mp3');
        dispatcher.on("end", end => { channel.leave() });
      })
      .catch(console.error)
  );

The problem is that the bot connect to the first channel and then directly connect to the second without having time to play the file in the first channel.

I think I have to look at the client.createVoiceBroadcast(); method. I tried to use it but I wasn't able to find a good example. Here is what I tried but it's not working too :

exports.run = (client, message, args, level) => {
  let voiceChannels = message.guild.channels.filter(channel => channel.type == 'voice');
  const broadcast = client.createVoiceBroadcast();
  broadcast.playFile('/home/pi/.discordbots/TARVIS/1.mp3');

  voiceChannels.forEach(channel =>
    channel.join()
      .then(connection => {
        const dispatcher = connection.playBroadcast(broadcast);
        dispatcher.on("end", end => { channel.leave() });
      })
      .catch(console.error)
  );

Expected result is the bot connects in each voice channel, one by one and play the mp3 file.

Thank you in advance for your help

EDIT

I tried to make an async function and use the await on the connection.playFile() but I still having the same problem. Bot connect to all voice channel but do not wait for the file to be played.

Here is the code I tried:

exports.run = async (client, message, args, level) => {

  async function play(voiceChannel) {
    console.log(voiceChannel.name + ` Type:` + voiceChannel.type + ` (` + voiceChannel.id + `)`);
    voiceChannel.join().then(async function (connection) {
      dispatcher = await connection.playFile('/home/pi/.discordbots/TARVIS/sncf.mp3');
      dispatcher.on('end', function () {
        voiceChannel.leave()
      });
    });
  }
  let voiceChannels = message.guild.channels.filter(channel => channel.type == 'voice');

  voiceChannels.map(vc => play(vc));

};

I'm pretty sure the solution is near... but I'm stuck... Does someone can help me to find the correct syntax ?

EDIT 2

Here is what I tried with your solution:

exports.run = async (client, message, args, level) => {

  async function play(voiceChannels) {
    for (let channel of voiceChannels) {
      console.log('Joining channel ' + channel.name);

      await channel.join().then(async (connection) => {
        console.log('Joined channel');

        let dispatcher = connection.playFile('/home/pi/.discordbots/TARVIS/sncf.mp3');
        await dispatcher.on('end', function () {
          channel.leave();
        });
      });
    }
  }

  let channels = message.guild.channels.filter(channel => channel.type == 'voice');
  console.log(channels);
  play(channels);

};

Answer 1

I might have found (somewhat) of a solution. I tried to recreate this problem in a JSFiddle so I could test it more easily. Here is my solution.

The core code is in the function joinChannels which can also be seen below

async function joinChannels () {
  for (let channel of channels) {
    await new Promise((resolve) => {
      console.log('Joining channel ' + channel.name);

      resolve(new Promise((resolve) => {
        setTimeout(() => {
          console.log('Done with channel ' + channel.name);
          resolve();
        }, 1000);
      }));
    });
  }
}

 

Now to rewrite this into a solution based on your context, here is my attempt (which is untested and thus might need some tweeking)

async function play(voiceChannels) {
  for (let channel of voiceChannels) {
    console.log('Joining channel ' + channel.name);

    await channel.join().then(async (connection) => {
      console.log('Joined channel');

      let dispatcher = connection.playFile('/home/pi/.discordbots/TARVIS/sncf.mp3');
      await dispatcher.on('end', function () {
        voiceChannel.leave();
      });
    });
  }
}

Give it a go and let me know how it turns out. If you have questions, I'm happy to help

Answer 2

Here is my workarround. I used the setTimeoutto enqueue channel voice with a timer of 10s I know is a bit dirty but it works

exports.run = async (client, message, args, level) => {

  async function play(channel) {
    await channel.join().then(async (connection) => {
      let dispatcher = await connection.playFile('/home/pi/.discordbots/TARVIS/offline.m4a');
      await dispatcher.on('end', function () {
        channel.leave();
      });
    });
  }

  let timer = 1000;
  client.ShowSuccess('Démarrage des annonces vocales');
  message.guild.channels.forEach(async (channel) => {
    if (channel.type == 'voice' && channel.members.size > 0) {
      client.ShowSuccess('Annonce dans le salon ' + channel.name + ' pour ' + channel.members.size + ' membre(s)', message.channel);
      client.logger.log('Annonce dans le salon ' + channel.name + ' pour ' + channel.members.size + ' membre(s)');
      setTimeout(function () {
        play(channel);
      }, timer);
      timer = timer + 10000;
    }
  });
  setTimeout(function () {
    client.ShowSuccess('Annonces vocales terminées');
  }, timer);
};