I have a UITextView to which I have attached a gesture recognizer as follows:
let testTapGestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(textTextViewTapped(gestureRecognizer:)))
testTapGestureRecognizer.cancelsTouchesInView = false
testTapGestureRecognizer.delaysTouchesBegan = false
testTapGestureRecognizer.delaysTouchesEnded = false
if textTextView != nil {
textTextView!.addGestureRecognizer(testTapGestureRecognizer)
}
The selector mentioned above is as follows:
@objc func textTextViewTapped(gestureRecognizer: UIGestureRecognizer) {
print("testTextViewTapped called.")
}
Every time I tap the UITextView, I can see the message above printed on the console. However, the keyboard doesn't appear any more.
I found Apple's doc confusing here: Here, it says that
A gesture recognizer doesn’t participate in the view’s responder chain.
which I am interpreting as that any gestures are also sent to the view and up the chain, as is normal.
Later on the same page, it says,
If a gesture recognizer recognizes its gesture, the remaining touches for the view are cancelled.
which means that if an attached gesture recognizer is able to understand a gesture as the one it is supposed to recognize, then it will prevent it from being delivered to the view to which it is attached. Further, it specifies 3 properties that should be able to stop the gesture recognizer from doing that. I have set all three of them to false in my code, as shown above.
What is actually happening here and how do I allow the UITextView to interpret the touches normally and also be able to use a gesture recognizer?
if x != nil { x!... }
is a bad pattern in Swift. You should do:if let x = x { x... }
. – rmaddyUITextField
in aUITextView
? – rmaddy