It's possible, but first you would need to convert the glob matches with "rain*" into "rain" by using dfm_lookup(). (Note: there are other ways to do this, such as tokenizing and then using tokens_lookup(), or tokens_replace(), but I think the lookup approach is more straightforward and this is also what you asked in the question.
Also note that for feature similarity, you must have more than a single document, which explains why I added two more here.
txt <- c("It is raining. It rains a lot during the rainy season",
"Raining today, and it rained yesterday.",
"When it's raining it must be rainy season.")
rain_dfm <- dfm(txt)
Then use a dictionary to convert glob matches (the default) with "rain*" to "rain", while keeping the other features. (In this particular case, you are correct that dfm_wordstem() could have accomplished the same thing.)
rain_dfm <- dfm_lookup(rain_dfm,
dictionary(list(rain = "rain*")),
exclusive = FALSE,
capkeys = FALSE)
rain_dfm
## Document-feature matrix of: 3 documents, 17 features (52.9% sparse).
## 3 x 17 sparse Matrix of class "dfm"
## features
## docs it is rain . a lot during the season today , and yesterday when it's must be
## text1 2 1 3 1 1 1 1 1 1 0 0 0 0 0 0 0 0
## text2 1 0 2 1 0 0 0 0 0 1 1 1 1 0 0 0 0
## text3 1 0 2 1 0 0 0 0 1 0 0 0 0 1 1 1 1
And now, you can compute the cosine similarity for the target feature of "rain":
textstat_simil(rain_dfm, selection = "rain", method = "cosine", margin = "features")
## rain
## it 0.9901475
## is 0.7276069
## rain 1.0000000
## . 0.9801961
## a 0.7276069
## lot 0.7276069
## during 0.7276069
## the 0.7276069
## season 0.8574929
## today 0.4850713
## , 0.4850713
## and 0.4850713
## yesterday 0.4850713
## when 0.4850713
## it's 0.4850713
## must 0.4850713
## be 0.4850713