How to create Spring Boot controller

Question

I have a spring boot application that needs a controller that can handle the following request:

The request is sent by another service through the Post method..

Headers

accept-encoding: gzip,deflate

user-agent: Apache-HttpClient/4.3.6 (java 1.5)

connection: Keep-Alive

host: webhook.site

content-type: application/x-www-form-urlencoded

content-length: 558

Query strings:(empty)

Form values

BillNumber: 41492032464

BillValue: 600000.0

Description: Description

I have this controller, but my application returns an HTTP Error 406:

@RequestMapping(value = "/bills", method = RequestMethod.POST, headers = "Accept=application/x-www-form-urlencoded")
    @ResponseBody
    @Transactional
    public void createBill(UriComponentsBuilder uriComponentsBuilder, final HttpServletRequest request,
            final HttpServletResponse response) throws IOException {
}

How should this controller be implemented in my spring boot app?

Many Thanks!

Can you more explain ! Do want to khnow how to call a service rest ? or you want to create a service rest witch create a bill ? if yes so can you give your object that you want to send to your service — TinyOS
simply this is the request that my controller must handle, does not return anything it's void — AlejoDev

TinyOS TinyOS · Accepted Answer · 2018-11-16T01:12:01

It's not very clear for me but if you use spring boot you can of course create a controller , service and repository or dao. Indeed, your controller will call your service witch will call the repository.

Let's suppose that you have a client witch call your api.

So the call will look like :

// Suppose that is a spring boot project

Class A {

@Autowired 
RestTemplate restTemplate;

public void create(){

    HttpHeaders headers = new HttpHeaders();
    headers.setAccept(Arrays.asList(MediaType.APPLICATION_JSON));
    headers.setContentType((MediaType.APPLICATION_JSON));
    headers.add("X-yourCustom-context", "yourCustom");

    UriComponentsBuilder builder = UriComponentsBuilder.fromHttpUrl(your_service_url)
                    .queryParam("params1", "value".queryParam("params2", value2));
    HttpEntity<?> entity = new HttpEntity<>(headers);

    restTemplate.exchange(builder.build().encode().toUri(), HttpMethod.POST, entity, null); // if you want to return an objectr you put it rather than the null

}

}

Th service api :

@RestController
public class YourController {
    @Autowired
    private YourService service;

    @Autowired
    private ObjectMapper objectMapper;


    @PostMapping(value = "/bills")
    //@ResponseBody if you do not return any think you can not use it
    // @CrossOrigin if you want to call your reste from an external project like javascript or angular
    //@Transactional you can put it on the top of your service methode
    public void createBill(@RequestParam(value = "params1", required = true) String params1, 
    @RequestParam(value = "params2", required = true) String params2,
    @RequestHeader(value = "X-yourCustom-context", required = true) String yourContxt) throws IOException {

    // You can then convert your x-context to an object that you have already by using objectMapper.readValue
    // Finaly you call you service to create the bill and you passe as params what you get fron the client 
}
}

I hope it meets your needs :)

How to create Spring Boot controller

1 Answers