python - pyspark error does not exist in the jvm error when initializing SparkContext

Question

I am using spark over emr and writing a pyspark script, I am getting an error when trying to

from pyspark import SparkContext
sc = SparkContext()

this is the error

File "pyex.py", line 5, in <module>
    sc = SparkContext()   File "/usr/local/lib/python3.4/site-packages/pyspark/context.py", line 118, in __init__
    conf, jsc, profiler_cls)   File "/usr/local/lib/python3.4/site-packages/pyspark/context.py", line 195, in _do_init
    self._encryption_enabled = self._jvm.PythonUtils.getEncryptionEnabled(self._jsc)   File "/usr/local/lib/python3.4/site-packages/py4j/java_gateway.py", line 1487, in __getattr__
    "{0}.{1} does not exist in the JVM".format(self._fqn, name)) py4j.protocol.Py4JError: org.apache.spark.api.python.PythonUtils.getEncryptionEnabled does not exist in the JVM

I found this answer stating that I need to import sparkcontext but this is not working also.

Answer 1

PySpark recently released 2.4.0, but there's no stable release for spark coinciding with this new version. Try downgrading to pyspark 2.3.2, this fixed it for me

Edit: to be more clear your PySpark version needs to be the same as the Apache Spark version that is downloaded, or you may run into compatibility issues

Check the version of pyspark by using

pip freeze

Answer 2

I just had a fresh pyspark installation on my Windows device and was having the exact same issue. What seems to have helped is the following:

Go to your System Environment Variables and add PYTHONPATH to it with the following value: %SPARK_HOME%\python;%SPARK_HOME%\python\lib\py4j-<version>-src.zip:%PYTHONPATH%, just check what py4j version you have in your spark/python/lib folder.

The reason why I think this works is because when I installed pyspark using conda, it also downloaded a py4j version which may not be compatible with the specific version of spark, so it seems to package its own version.

Answer 3

You need to set the following environments to set the Spark path and the Py4j path.
For example in ~/.bashrc:

export SPARK_HOME=/home/hadoop/spark-2.1.0-bin-hadoop2.7
export PYTHONPATH=$SPARK_HOME/python:$SPARK_HOME/python/lib/py4j-0.10.4-src.zip:$PYTHONPATH
export PATH=$SPARK_HOME/bin:$SPARK_HOME/python:$PATH

And use findspark at the top of the your file:

import findspark
findspark.init()

Answer 4

Try adding this at the top of the file:

import findspark
findspark.init()

See https://github.com/minrk/findspark

Answer 5

Use SparkContext().stop() at the end of the program to stop this situation.

Answer 6

The following steps solved my issue: - Downgrading it to 2.3.2 - adding PYTHONPATH as System Environment Variable with value %SPARK_HOME%\python;%SPARK_HOME%\python\lib\py4j-<version>-src.zip:%PYTHONPATH% Note: use proper version in the value given above, don't copy exactly.

Answer 7

Instead of editing the Environment Variables, you might just ensure that the Python environment (the one with pyspark) also has the same py4j version as the zip file present in the \python\lib\ dictionary within you Spark folder. E.g., d:\Programs\Spark\python\lib\py4j-0.10.7-src.zip on my system, for Spark 2.3.2. It's the py4j version shipped as part of the Spark archive file.

Answer 8

Just to make it simple,It's all about python and java couldn't talk because the medium the have to speak out (py4j) are different, that's it.I had same issue and all those above answers are valid and will work if you use them correctly, It's either you define a system variable to tell both which py4j they should use, or you can make some un-installation and installation back so that everyone will be on same page.

Answer 9

when i download new version pip install from anaconda command prompt, i get same issue.

when i use top of the code file:
import findspark findspark.init("c:\spark")

this code solved my problem.

Answer 10

Try to install spark 2.4.5 version, and set spark home path to this version. Even I faced the issue after changing the version, it got resolved for me.