33
votes

I dont want to use html file, but only with django I have to make POST request.

Just like urllib2 sends a get request.

5

5 Answers

34
votes

In Python 2, a combination of methods from urllib2 and urllib will do the trick. Here is how I post data using the two:

post_data = [('name','Gladys'),]     # a sequence of two element tuples
result = urllib2.urlopen('http://example.com', urllib.urlencode(post_data))
content = result.read()

urlopen() is a method you use for opening urls. urlencode() converts the arguments to percent-encoded string.

38
votes

Here's how you'd write the accepted answer's example using python-requests:

post_data = {'name': 'Gladys'}
response = requests.post('http://example.com', data=post_data)
content = response.content

Much more intuitive. See the Quickstart for more simple examples.

7
votes
5
votes

You can use urllib2 in django. After all, it's still python. To send a POST with urllib2, you can send the data parameter (taken from here):

urllib2.urlopen(url[, data][, timeout])

[..] the HTTP request will be a POST instead of a GET when the data parameter is provided

1
votes

Pay attention, that when you're using 🐍 requests , and make POST request passing your dictionary in data parameter like this:

payload = {'param1':1, 'param2':2}
r = request.post('https://domain.tld', data=payload)

you are passing parameters form-encoded.

If you want to send POST request with only JSON (most popular type in server-server integration) you need to provide a str() in data parameter. In case with JSON, you need to import json lib and make like this:

 payload = {'param1':1, 'param2':2}
 r = request.post('https://domain.tld', data=json.dumps(payload))`

documentation is here