Sendgrid substitutionWrappers are not working as expected

Question

I working with sendGrid Mail Api to send mail using firebase cloud functions

Here is my code for sending email using sendGrid/Mail API

 studentList.forEach(s => {
            var e = {
                to: s.email,
                from: '[email protected]',
                subject: "Mail Using Send Grid",
                templateId: templateId,
                substitutionWrappers: ['{{', '}}'],
                substitutions: {
                   name: s.name
                }
            }
            mailArray.push(e);
        });
        return sendGrid.send(mailArray).then(() => {
            var message = { message: "Mail Successfully sent" };
            return response.status(200).send(message);
        });

My template in send Grid See the image

Mail is sent but the placeholders are not replaced with substitutionWrappers. Please help me in, as i'm new to this.

Dragos Lupei Dragos Lupei · Accepted Answer · 2018-09-10T13:04:59

Install the latest version of @sendgrid/mail package and follow the instructions on following link on official documentation Transactional Templates Use Case

The thing is now you have to use dynamic_template_data instead of substitutions. You also can delete the substitutionWrappers property,because starting with v3 API, there's no need to specify the substitution wrappers as it will assume that you're using {{ curly braces}}.

Here is an example that should work:

constudentList.forEach(s => {
        var e = {
            to: s.email,
            from: '[email protected]',
            subject: "Mail Using Send Grid",
            templateId: templateId,
            dynamic_template_data: {
               name: s.name
            }
        }
        mailArray.push(e);
    });
    return sendGrid.send(mailArray).then(() => {
        var message = { message: "Mail Successfully sent" };
        return response.status(200).send(message);
    });

Sendgrid substitutionWrappers are not working as expected

1 Answers