Jenkins build not executing `docker tag` command correctly

0
votes

I am attempting to build https://github.com/ansible/awx.

To setup my Jenkins environment, I deployed Ubuntu in AWS, installed the development tools, docker, and Jenkins, and joined the jenkins user to the docker group. Then, I setup Jenkins with the default configuration.

After Jenkins was setup, I created a "freestyle project," set the SCM git repository URL to https://github.com/ansible/awx.git, then added an execute shell build step to the following:

cp awx/settings/local_settings.py.docker_compose awx/settings/local_settings.py
make docker-compose-build

Build. Fairly simple, right?! No. The build creates a docker image as it is supposed to. However, the final command of the Makefile is to tag docker image using the following command:

docker tag ansible/awx_devel gcr.io/ansible-tower-engineering/awx_devel:origin/devel

However, this returns the following:

Error parsing reference: "gcr.io/ansible-tower-engineering/awx_devel:origin/devel" is not a valid repository/tag: invalid reference format

This error does NOT happen if I run the make command in a similar environment. It does NOT happen if I run the docker tag command in a similar environment.

P.S. I have tried explicitly setting the shell.

1
gitdockerjenkinsansibleansible-awx

1 Answers

4
votes

https://docs.docker.com/engine/reference/commandline/tag/

A tag name must be valid ASCII and may contain lowercase and uppercase letters, digits, underscores, periods and dashes. A tag name may not start with a period or a dash and may contain a maximum of 128 characters.

So, the problem is / in your tag name. Try tagging with origin-devel.