0
votes

I need to copy child elements into the parent element.

input

<csv>
<row>
    <stuff>a</stuff>
    <more>1</more>
    <evenmore>123</evenmore>
    <row>
        <other>1345</other>
        <stuff>dga</stuff>
    </row>
</row>
<row>
    <stuff>b</stuff>
    <more>2</more>
    <evenmore>456</evenmore>
    <row>
        <other>4576</other>
        <stuff>jzj</stuff>
    </row>
</row>
</csv>

desired output

<csv>
<row>
    <stuff>a</stuff>
    <more>1</more>
    <evenmore>123</evenmore>
    <other>1345</other>
    <stuff>dga</stuff>
</row>
<row>
    <stuff>b</stuff>
    <more>2</more>
    <evenmore>456</evenmore>
    <other>4576</other>
    <stuff>jzj</stuff>
</row>
</csv>

What I tried (the output stays the same like the input):

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:strip-space elements="*"/>
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>

<xsl:template match="@* | node()">
    <xsl:copy>
        <xsl:apply-templates/>
    </xsl:copy>
</xsl:template>

<xsl:template match="row">
    <xsl:copy>
        <xsl:apply-templates/>
        <xsl:apply-templates select="child::row/row/other | child::row/row/stuff"/>
    </xsl:copy>
</xsl:template>
</xsl:stylesheet>

I am sure to miss something very simple here. It should not be a problem, that the child element has the same name as the parent element?

1

1 Answers

2
votes

You really need your second template to only match the child row, and not the parent one. Then you can select its children, but just not copy it itself

Try this XSLT

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:strip-space elements="*"/>
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>

<xsl:template match="@* | node()">
    <xsl:copy>
        <xsl:apply-templates/>
    </xsl:copy>
</xsl:template>

<xsl:template match="row/row">
    <xsl:apply-templates/>
</xsl:template>
</xsl:stylesheet>