0
votes

I have this following test code:

public static final String[] list = {
    "apple","ball","cat","dog","egg","fan","girl","hat","igloo","jerk"  
};

...

HashMap<DoubleKey<Integer, Integer>, String> hm = new HashMap<DoubleKey<Integer, Integer>, String>();
Set<DoubleKey<Integer, Integer>> s = new TreeSet<DoubleKey<Integer, Integer>>();
Random g = new Random();
for(int i=0; i<10; i++){
    int first = g.nextInt(9999) + 1000; 
    int second = g.nextInt(9999) + 1000; 
    DoubleKey<Integer, Integer> k1 = new DoubleKey<Integer, Integer>(first, second);
    DoubleKey<Integer, Integer> k2 = new DoubleKey<Integer, Integer>(first, second);
    s.add(k1);
    hm.put(k2, list[i]);
}

Set<DoubleKey<Integer, Integer>> ts = hm.keySet();
Iterator<DoubleKey<Integer, Integer>> itr = ts.iterator();
while(itr.hasNext()){
    DoubleKey<Integer, Integer> k = itr.next(); 
    System.out.println(k.getFirstKey().toString() + " + " + k.getSecondKey().toString() + " -> " + hm.get(k).toString());
}

System.out.println("----");
Iterator<DoubleKey<Integer, Integer>> sItr = s.iterator();
while(sItr.hasNext()){
    DoubleKey<Integer, Integer> k = sItr.next();
    String currStr = hm.get(k);
    System.out.println(k.getFirstKey().toString() + " + " + k.getSecondKey().toString() + " -> " + currStr);
}

What I did is to create a Custom Generic Class DoubleKey<K, J> to contain a key having two parts. As you can see, the Set s and the keys of HashMap hm are have the same components, but was instantiated differently (k1 = k2). When I try to get a value using the keys on s to hm, it returns null, though at the first printing it shows the correct mapping.

Sample Output:

3922 + 2544 -> girl
9267 + 3750 -> hat
3107 + 10929 -> apple
5162 + 8834 -> fan
8786 + 1125 -> cat
10650 + 4078 -> egg
3808 + 7363 -> jerk
1364 + 7657 -> dog
1364 + 4412 -> ball
1583 + 1460 -> igloo
----
10650 + 4078 -> null
1364 + 4412 -> null
1364 + 7657 -> null
1583 + 1460 -> null
3107 + 10929 -> null
3808 + 7363 -> null
3922 + 2544 -> null
5162 + 8834 -> null
8786 + 1125 -> null
9267 + 3750 -> null

This is my DoubleKey implemention:

public class DoubleKey<K extends Comparable<K>,J extends Comparable<J>> implements Comparable<DoubleKey<K,J>>{

    private K key1;
    private J key2;

    public DoubleKey(K key1, J key2){
        this.key1 = key1;
        this.key2 = key2;
    } 

    public K getFirstKey(){
        return this.key1;
    }

    public J getSecondKey(){
        return this.key2;
    }

    // need for Comparable interface
    public int compareTo(DoubleKey<K,J> aThat){
        // NOTE: check for nulls
        return (this.key1.toString() + this.key2.toString()).compareTo(aThat.key1.toString() + aThat.key2.toString());
    }

    public boolean equals(DoubleKey<K,J> aThat){
        return (this.key1.toString() + this.key2.toString()).equals(aThat.key1.toString() + aThat.key2.toString());
    }

}

How did it happened? Can two objecst (in this case from a custom generic) be different eve3n if they have instantiated with 2 same values? How can I correct this? I hope someone can help me here. Thanks!

3
There's way too much code here! Please can you cut your example down a lot, so that someone might have the patience to look at it all. - Oliver Charlesworth
Where is the DoubleKey class's hashCode method override? - Hovercraft Full Of Eels
I was trying to explain it the best I can. I'm sorry. - John Bautista
I don't think there's too much code. There's just enough. Sometimes a decent length explanation is required. - GaryF

3 Answers

4
votes

Additionally to .hashCode(), you should have an implementation of equals(Object), not (only) equals(DoubleKey<...>), since otherwise you'll have two independent methods here (and only the first one is actually called by the HashMap). Here is a proposal:

public boolean equals(Object other) {
    if(this == other)
       return true;
    if(!(other instanceof DoubleKey))
       return false;
    DoubleKey that = (DoubleKey)other;
    return (this.key1 == null ? that.key1 == null : this.key1.equals(that.key1)) &&
           (this.key2 == null ? that.key2 == null : this.key2.equals(that.key2));
}

The hashCode method should be made to fit this, too, for example like this:

public int hashCode() {
    return key1.hashCode() * 3 + key2.hashCode() * 5;
}

Your key1.toString()+key2.toString() comparison is a bit dangerous, as it lets (1, 21).equals((12,1)) be true, which is usually not intended. The same is true for your compareTo method - compare the components using their compareTo method, not the concatenated String.

3
votes

Learn this lesson now: If you override the equals method (as you have done), then you MUST override the hashcode method too. That method is used for various things, including looking up items in HashMaps.

1
votes

Where is DoubleKey class's hashCode method override? I don't think that it will work as a proper key unless you implement this because otherwise your two objects will be considered different.