Arduino interrupts functions

Question

I want to call some functions at the rising edge and falling edge of a square wave pulses. I used attachInterrupt(digitalPinToInterrupt(interruptPin), udara, RISING) for rising edge and attachInterrupt(digitalPinToInterrupt(interruptPin), blank,FALLING) for falling edge. But I didn`t get the serial outputs of rise and fall conservatively. what is the answer for the problem? My code is written as follows.

enter code here
const byte interruptPin = 2;

void setup() {
    Serial.begin(9600);
    pinMode(interruptPin, INPUT);

}

void loop() {
    attachInterrupt(digitalPinToInterrupt(interruptPin), udara, RISING);
    attachInterrupt(digitalPinToInterrupt(interruptPin), blank, FALLING);
}

void udara() {
    Serial.println("rise");

}`

void blank() {
    Serial.println("fall");
}

Why are you attaching in 'loop()'? Wouldn't it make more sense to attach once in 'setup()'? — Jay Buckman

hcheung hcheung · Accepted Answer · 2018-05-01T13:16:41

The attachInterrupt() should be part of setup(), not the loop(), as it is used to setup the event trigger and callback.

const byte interruptPin = 2;

void setup() {
    Serial.begin(9600);
    pinMode(interruptPin, INPUT);
    attachInterrupt(digitalPinToInterrupt(interruptPin), udara, RISING);
    attachInterrupt(digitalPinToInterrupt(interruptPin), blank, FALLING);
}

void loop() {

}

void udara() {
    Serial.println("rise");
}

void blank() {
    Serial.println("fall");
}

Arduino interrupts functions

2 Answers