Safely override C++ virtual functions

Question

I have a base class with a virtual function and I want to override that function in a derived class. Is there some way to make the compiler check if the function I declared in the derived class actually overrides a function in the base class? I would like to add some macro or something that ensures that I didn't accidentally declare a new function, instead of overriding the old one.

Take this example:

class parent {
public:
  virtual void handle_event(int something) const {
    // boring default code
  }
};

class child : public parent {
public:
  virtual void handle_event(int something) {
    // new exciting code
  }
};

int main() {
  parent *p = new child();
  p->handle_event(1);
}

Here parent::handle_event() is called instead of child::handle_event(), because the child's method misses the const declaration and therefore declares a new method. This could also be a typo in the function name or some minor difference in the parameters types. It can also easily happen if the interface of the base class changes and somewhere some derived class wasn't updated to reflect the change.

Is there some way to avoid this problem, can I somehow tell the compiler or some other tool to check this for me? Any helpful compiler flags (preferably for g++)? How do you avoid these problems?

Answer 1

Since g++ 4.7 it does understand the new C++11 override keyword:

class child : public parent {
    public:
      // force handle_event to override a existing function in parent
      // error out if the function with the correct signature does not exist
      void handle_event(int something) override;
};

Answer 2

Something like C#'s override keyword is not part of C++.

In gcc, -Woverloaded-virtual warns against hiding a base class virtual function with a function of the same name but a sufficiently different signature that it doesn't override it. It won't, though, protect you against failing to override a function due to mis-spelling the function name itself.

Answer 3

As far as I know, can't you just make it abstract?

class parent {
public:
  virtual void handle_event(int something) const = 0 {
    // boring default code
  }
};

I thought I read on www.parashift.com that you can actually implement an abstract method. Which makes sense to me personally, the only thing it does is force subclasses to implement it, no one said anything about it not being allowed to have an implementation itself.

Answer 4

In MSVC, you can use the CLR override keyword even if you're not compiling for CLR.

In g++, there's no direct way of enforcing that in all cases; other people have given good answers on how to catch signature differences using -Woverloaded-virtual. In a future version, someone might add syntax like __attribute__ ((override)) or the equivalent using the C++0x syntax.

Answer 5

In MSVC++ you can use keyword override

class child : public parent {
public:
  virtual void handle_event(int something) <b>override</b> {
    // new exciting code
  }
};

override works both for native and CLR code in MSVC++.

Answer 6

Make the function abstract, so that derived classes have no other choice than to override it.

@Ray Your code is invalid.

class parent {
public:
  virtual void handle_event(int something) const = 0 {
    // boring default code
  }
};

Abstract functions cannot have bodies defined inline. It must be modified to become

class parent {
public:
  virtual void handle_event(int something) const = 0;
};

void parent::handle_event( int something ) { /* do w/e you want here. */ }

Answer 7

I would suggest a slight change in your logic. It may or may not work, depending on what you need to accomplish.

handle_event() can still do the "boring default code" but instead of being virtual, at the point where you want it to do the "new exciting code" have the base class call an abstract method (i.e. must-be-overridden) method that will be supplied by your descendant class.

EDIT: And if you later decide that some of your descendant classes do not need to provide "new exciting code" then you can change the abstract to virtual and supply an empty base class implementation of that "inserted" functionality.

Answer 8

Your compiler may have a warning that it can generate if a base class function becomes hidden. If it does, enable it. That will catch const clashes and differences in parameter lists. Unfortunately this won't uncover a spelling error.

For example, this is warning C4263 in Microsoft Visual C++.

Answer 9

C++11 override keyword when used with the function declaration inside the derived class, it forces the compiler to check that the declared function is actually overriding some base class function. Otherwise, the compiler will throw an error.

Hence you can use override specifier to ensure dynamic polymorphism (function overriding).

class derived: public base{
public:
  virtual void func_name(int var_name) override {
    // statement
  }
};

Answer 10

class MyClass {
public:
 
  MyClass() {}
  virtual uint32_t someFunction(bool param = false) {
    if (param) {
      std::cout << "This is an example virtual function with default code" << std::endl;
    }
    return 1100;  //just for return something
  };

 

• then you can override the function as you need

class MyClass2 : public MyClass  {
public:
  MyClass2();
  uint32_t someFunction(bool param) override;
};

uint32_t MyClass2::someFunction(bool verbose) {
  std::cout << "This is new implementation for virtual method " << std::endl;

}