Note from maintainers: Support for Coffeescript is deprecated and will be removed in Bokeh 2.0.
The other day, I asked about how to control tickers:
How to show only evey nth categorical tickers in Bokeh
Now I need to supply n from outside of Coffeescript, where n is the every n-th ticker.
Based on the code snippet provided by bigreddot and by referring to the code examples shown below links:
How do I use custom labels for ticks in Bokeh?
I came up with the following very minimal code although I don't have knowledge about Coffescript. In fact, however, it does not work.
EDIT:
1) Below is the complete code that you can copy and run. 2) Bokeh version: 0.12.13 Python: 3.6.5
from bokeh.core.properties import Float, Instance, Tuple, Bool, Enum, String,Int
from bokeh.models import TickFormatter, CategoricalTicker
from bokeh.io import show, output_file
from bokeh.plotting import figure
class MyTicker(CategoricalTicker):
__implementation__ = """
import {CategoricalTicker} from "models/tickers/categorical_ticker"
import * as p from "core/properties"
export class MyTicker extends CategoricalTicker
type: "MyTicker"
@define {
nth: [ p.Int ]
}
get_ticks: (start, end, range, cross_loc) ->
ticks = super(start, end, range, cross_loc)
# drops every other tick -- update to suit your specific needs
ticks.major = ticks.major.filter((element, index) -> index % this.nth == 0)
return ticks
"""
nth = Int(default=2)
output_file("bars.html")
fruits = ['Apples', 'Pears', 'Nectarines', 'Plums', 'Grapes', 'Strawberries']
p = figure(x_range=fruits, plot_height=250, title="Fruit Counts",
toolbar_location=None, tools="")
p.vbar(x=fruits, top=[5, 3, 4, 2, 4, 6], width=0.9)
p.xgrid.grid_line_color = None
p.y_range.start = 0
p.xaxis.ticker = MyTicker(nth=2)
show(p)
"this.nth" doesn't seem to work. The result is blank.