Printing/Fetching Vertex values from a path

Question

Just getting started with gremlin.

Printing out all the Vertex values worked out fine

gremlin> g.V().values()
==>testing 2
==>Cash Processing
==>Sales
==>Marketing
==>Accounting

I was able to find all the directly connected path between my Vertices.

gremlin> g.V().hasLabel('Process')
.repeat(both().simplePath())
.until(hasLabel('Process'))
.dedup().path()
==>[v[25],v[28]]
==>[v[25],v[26]]
==>[v[26],v[27]]
==>[v[26],v[25]]

Now am trying to print out the values in the path like ['Sales', 'Accounting'] instead of [v[25],v[28]]

Not been able to figure out a way yet

Already tried and failed with

Unfold: Does not get me 1-1 mapping

gremlin> g.V().hasLabel('Process').repeat(both().simplePath()).until(hasLabel('Process')).dedup().path().unfold().values() ==>Cash Processing ==>Accounting ==>Cash Processing ==>Sales ==>Sales ==>Marketing ==>Sales ==>Cash Processing
Path seems to be of a different data-type and does not support .values() function

gremlin> g.V().hasLabel('Process') .repeat(both().simplePath()) .until(hasLabel('Process')) .dedup().path().values()

org.apache.tinkerpop.gremlin.process.traversal.step.util.ImmutablePath cannot be cast to org.apache.tinkerpop.gremlin.structure.Element

Tried the following google searches and didnt get the answer
- gremlin print a path
- gremlin get values in a path
- and few more word twisting
Found one at here that was for java but that didnt work for me

l = []; g.V().....path().fill(l)

(but cant create list, Cannot set readonly property: list for class: org.apache.tinkerpop.gremlin.structure.VertexProperty$Cardinality )

I have running it on Gremlin console (running ./gremlin.sh)

Florian Hockmann Florian Hockmann · Accepted Answer · 2018-03-10T18:44:35

You can use the by step to modulate the elements inside the path. For example by supplying valueMap(true) to by you get the properties of the vertices, together with the vertex labels and their ids:

gremlin> g.V().repeat(both().simplePath()).times(1).dedup().path().by(valueMap(true))
==>[[id:1,name:[marko],label:person,age:[29]],[id:3,name:[lop],lang:[java],label:software]]
==>[[id:1,name:[marko],label:person,age:[29]],[id:2,name:[vadas],label:person,age:[27]]]
==>[[id:1,name:[marko],label:person,age:[29]],[id:4,name:[josh],label:person,age:[32]]]
==>[[id:2,name:[vadas],label:person,age:[27]],[id:1,name:[marko],label:person,age:[29]]]
==>[[id:3,name:[lop],lang:[java],label:software],[id:6,name:[peter],label:person,age:[35]]]
==>[[id:4,name:[josh],label:person,age:[32]],[id:5,name:[ripple],lang:[java],label:software]]

I used the modern graph which is one of TinkerPop's toy graphs that are often used for such examples. Your output will look a bit different and you may want to use something else than valueMap(true) for the by modulator. The TinkerPop documentation of the path step itself contains two more advanced examples for path().by() that you might want to check out.

Printing/Fetching Vertex values from a path

1 Answers