I'm rendering particles in a 2D game. Each particle is a quad (2 triangles). How can I make the drawing the fastest possible? All the particles has the same texture, I'm only changing it's positions.
Now I'm using a call to glVertexPointer and glDrawArrays for each particle. So I'm sending 4 vertices each time to the GPU.
Is there any other approach that could be faster?
I'm using OpenGL ES 1.1 (iPhone)
Thanks!
Every draw call you make (glDrawArrays) is expensive. Doing this once per particle is DEFINITELY way too often. All your particles can be drawn with a single draw call; just set up a big array of all the triangle verts and another big array with the texture coords, and call glVertexPointer/glDrawArrays once-- that's the power of glVertexPointer: arbitrary geometry of the same type in one call. :)
For what you're doing, you should also look into point sprites (GL_POINTS), which also function as tiny textured quads. They're 2D only, so you can't map your texture into the Z axis, but if your particles are just 2D quads of the same texture over and over, point sprites will likely do exactly what you want.
There's a way to do that all in one draw routine. I THINK it's by adding an extra vertex after each quad, which is the same as the previous vertex, but I could be wrong.
EDIT: After looking into it a bit, it looks like you need two in between; essentially one after, and one before. It does add up to quite a few extra vertexes, but I know from experience that it makes a HUGE positive difference on the iPhone to do it all in one draw operation (we were drawing text from a texture, so essentially the same thing).
EDIT2: Also note, I'm referring to using GL_TRIANGLE_STRIP - if you were using GL_TRIANGLES instead, you wouldn't need the extra vertices... except, then you'd be doing the same amount extra anyway, due to repeating 2 for each second triangle.
